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12345 [234]
3 years ago
6

Three times a larger number is 30 more than 5 times a smaller number. The sum of the larger number and 5 times the smaller numbe

r is 50. Let x be the smaller number and y be the larger number. Create a system and graph it to find the solution. What are the two numbers?
Mathematics
2 answers:
Andrews [41]3 years ago
8 0

Answer:

Three times a larger number is 30 more than 5 times a smaller number. The sum of the larger number and 5 times the smaller number is 50. Let x be the smaller number and y be the larger number. Create a system and graph it to find the solution. What are the two numbers?

Step-by-step explanation:

<em>If "y" is the largest number, and "x" the smallest number, it would look like this: </em>

3y = 5x + 30, <em>we cleared to add the two equations and it would be</em>: 3y - 5x = 30

y + 5x = 50

<em>Where</em>: 3y + y - 5x + 5x = 30 + 50

4y = 80; y = 80/4 = <u>20 = y </u>

<em>Now substituting the value of y in the equation would be:</em> 20 + 5x = 50; 5x = 50-20; 5x = 30; x = 30/5 = <u>6 = x </u>

<em>And the two values would be</em>:<u> 6 and 20</u>

slava [35]3 years ago
5 0
3y  = 5x + 30

y + 5x = 50 .......(1)

3y - 5x = 30 .....(2)        - rearranging the first equation.

Add (1) and (2):-

4y = 80

y = 20  
Now plug y = 20 into equation (1):-
20 + 5x = 50
5x = 30 
x = 6

The 2 numbers are 6 and 20.

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Wayne is hanging a string of lights 58 feet long around the three sides of his patio, which is adjacent to his house. The length
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Answer:

The length of the patio is 32 ft and the width is 13 ft

Step-by-step explanation:

see the attached figure to better understand the problem

Let

L ----> the length of his patio

W ---> the width of his patio

we know that

L+2W=58 ----> equation A

L=2W+6 ----> equation B

substitute equation B in equation A and solve for W

2W+6+2W=58

4W+6=58

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3 0
3 years ago
Q(a+1) - 2q(a) if q(x) = x²+3x+4​
siniylev [52]

q(x) =  {x}^{2} + 3x + 4

_________________________________

Step(1)

To find q(a) we just need to put a instead of x in q(x) function.

Let's do it...

q(a) =  {a}^{2} + 3a + 4

Multiply sides by -2 :

- 2q(a) =  - 2( {a}^{2} + 3a + 4)

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_________________________________

Step (2)

To find q(a+1) we just need to put a+1 instead of x in q(x) function.

Let's do it...

q(a + 1) =  ({a + 1})^{2} + 3(a + 1) + 4 \\

q(a + 1) =  {a}^{2} + 2a + 1 + 3a + 3 + 4 \\

q(a + 1) =  {a}^{2} + 5a + 8

_________________________________

Step (3)

q(a + 1) - 2q(a) =

{a}^{2} + 5a + 8 - 2 {a}^{2} - 6a - 8 =  \\

-  {a}^{2} - a  =  - a(a + 1)

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

8 0
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