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12345 [234]
3 years ago
6

Three times a larger number is 30 more than 5 times a smaller number. The sum of the larger number and 5 times the smaller numbe

r is 50. Let x be the smaller number and y be the larger number. Create a system and graph it to find the solution. What are the two numbers?
Mathematics
2 answers:
Andrews [41]3 years ago
8 0

Answer:

Three times a larger number is 30 more than 5 times a smaller number. The sum of the larger number and 5 times the smaller number is 50. Let x be the smaller number and y be the larger number. Create a system and graph it to find the solution. What are the two numbers?

Step-by-step explanation:

<em>If "y" is the largest number, and "x" the smallest number, it would look like this: </em>

3y = 5x + 30, <em>we cleared to add the two equations and it would be</em>: 3y - 5x = 30

y + 5x = 50

<em>Where</em>: 3y + y - 5x + 5x = 30 + 50

4y = 80; y = 80/4 = <u>20 = y </u>

<em>Now substituting the value of y in the equation would be:</em> 20 + 5x = 50; 5x = 50-20; 5x = 30; x = 30/5 = <u>6 = x </u>

<em>And the two values would be</em>:<u> 6 and 20</u>

slava [35]3 years ago
5 0
3y  = 5x + 30

y + 5x = 50 .......(1)

3y - 5x = 30 .....(2)        - rearranging the first equation.

Add (1) and (2):-

4y = 80

y = 20  
Now plug y = 20 into equation (1):-
20 + 5x = 50
5x = 30 
x = 6

The 2 numbers are 6 and 20.

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Solve for x use the completing the square method x^2+6x=5
Mrac [35]

Answer:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

Step-by-step explanation:

x^{2}+6x-5=0

we divide the coefficient of the X by half :

in this case: 6/2 = 3 , then we do the following

The result obtained is raised to square power:  3^2=9

we sum and subtract by 9 to maintain the balance of the equation:

x^{2}+6x+9-9-5=0

we have:

(x+3)^{2}-9-5=0

(x+3)^{2} = 14

lets apply square root on both sides of the equation:

\sqrt{(x+3)^{2}}=\sqrt{14}

we know:

\sqrt{a^{2}} = abs(a)

so we have:

abs(x+3)=\sqrt{14}

from where two solutions are obtained

x_{1} + 3 =\sqrt{14} \\\\x_{2} + 3 =-\sqrt{14}

finally we have:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

5 0
3 years ago
Read 2 more answers
How to add fractions? with unlike denominators
stellarik [79]

Answer:

The recipe calls for 19/12 or 1 7/9 cups.


Step-by-step:

In order to get this answer, we have to add all three fractions together. First, we have to find the LCM (Least Common Multiple) between the three denominators:

2: 2, 4, 6, 8, 10, 12

3: 3,6,9,12

4: 4,8,12

The LCM between these three denominators is 12.

4x3=12

2x6=12

3x4=12

You now multiply the numerator by the same number you multiplied by for the denominator in order to get 12:

3/4 becomes 9/12

1/2 becomes 6/12

1/3 becomes 4/12

We now add all the fractions together:

9/12+6/12+4/12= 19/12

We got 19/12 but the answer is an improper fraction so we turn it into a mixed number:

12x1=12 (7 remaining)

This is written as 1 7/12.

Hope this helps! :)

<h3>CloutAnswers</h3>
3 0
3 years ago
Help please due now
umka21 [38]

Answer:

hii here is your answer

6 0
3 years ago
Hello, I have a Pi Day Question for you, it's pretty simple.
stira [4]
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7 0
3 years ago
Find the original price if the sale price of the cell phone is $205.50
Arlecino [84]

Answer:

$293.6

Step-by-step explanation:

Here is the complete question: A cell phone is on sale for 30% off. Find the original price if the sale price of the cell phone is $205.50.

Given: Sale price of cell phone is $205.50

           Discount= 30%

As 30% discount is given on original price or we can say 70% of original price is $205.50.

∴ Let the original price be x.

⇒ \frac{70}{100} \times x= 205.50

Now, cross multiplying both side.

⇒ x= \frac{100}{70} \times 205.5

∴ x= $293.6

The original price of cell phone is $293.6.

7 0
3 years ago
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