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Katena32 [7]
3 years ago
14

How many carbon dioxide molecules should be added to the products side to obey the law of conservation of matter?

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
3 0

Answer:

four A

Explanation:

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To understand the relation between the strength of an acid or a base and its pKa and pKb values. The degree to which a weak acid
elena-14-01-66 [18.8K]

Answer:

pKa = 3.675

Explanation:

  • pKa = - Log Ka

∴ <em>C</em> X-281 = 0.079 M

∴ pH = 2.40

let X-281 a weak acid ( HA ):

∴ HA ↔ H+ + A-

⇒ Ka = [H+] * [A-] / [HA]

mass balance:

⇒<em> C</em> HA = 0.079 M = [HA] + [A-]

⇒ [HA] = 0.079 - [A-]

charge balance:

⇒ [H+] = [A-] + [OH-]... [OH-] is negligible; it comes from to water

⇒ [H+] = [A-]

∴ pH = - log [H+] = 2.40

⇒ [H+] = 3.981 E-3 M

replacing in Ka:

⇒ Ka = [H+]² / ( 0.079 - [H+] )

⇒ Ka = ( 3.981 E-3 )² / ( 0.079 - 3.981 E-3 )

⇒ Ka = 2.113 E-4

⇒ pKa = - Log ( 2.113 E-4 )

⇒ pKa = 3.675

8 0
3 years ago
Complete the sentence:
Komok [63]

equilibrium

Heat transfers from a body with high temperature to a body with low temperature until both bodies are in the same temperature.

3 0
3 years ago
Calculate Ho298 for the process
Inga [223]

Explanation:

As per the Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

Hence, according to this law the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

Sb + \frac{3}{2}Cl_2 \rightarrow SbCl_{3}    \Delta H^0_1 =  -314 kJ  ..........(1)

SbCl_{3} + Cl_2 \rightarrow SbCl_{5}    \Delta H^0_2 = -80kJ   ..............(2)

The final reaction is as follows:  

Sb + \frac{5}{2}Cl_{2} \rightarrow SbCl_{5}  \Delta H^0_3 = ?  .............(3)

Therefore, adding (1) and (2) we get the final equation (3) and value of \Delta H^{0}_{3} at 298 K will be as follows.

             \Delta H^{0}_{3} = \Delta H^{0}_{1} + \Delta H^{0}_{2}    

                       = -314 kJ + (-80) kJ

                       = -394 kJ

Thus, we can conclude that H^{o} at 298 K for the given process is -394 kJ.

4 0
3 years ago
as any personal information of clients, customers, employees, guests, or anyone else exposed in the incident?
Elena L [17]

Answer:

"Protecting the privacy of your employees is critical to the long term success of your business. Senior leadership, high-profile executives and their families, as well as other customer-facing employees are particularly vulnerable to targeting to bad actors when their personal information is exposed. Other potential sources of danger include disgruntled employees, ex-employees and even customers."

Hope this helps :)

8 0
3 years ago
What is the chemical formula for monosaccharides?
goldfiish [28.3K]
Since monosaccharides are the simplest units of carbohydrates, then they are made up of carbon, hydrogen, and oxygen atoms. 

empirical formula : CxH2xOx
where
x  \geqslant 3
Monosaccharides can be classified by the number x of carbon atoms they contain: triose(3) tetrose (4), pentose (5), hexose (6), heptose (7), and so on.
5 0
3 years ago
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