3 years ago

At a certain temperature Kc = 9.0 for the equilibrium 24() ⇔ 22(). What is

Chemistry

1 answer:

Iteru [2.4K]3 years ago

5 0

Answer:

Explanation:

You might be interested in

A student used standard solutions of aspirin in a FeCl3-KCl-HCl mixture to plot a graph of molarity versus absorbance for dilute

kvasek [131]

Answer:

is any thing which has mass volume and empty space

8 0

2 years ago

How do I balance a chemical equation?

bogdanovich [222]

Answer:

Concept: Chemical Analysis

Start by taking inventory of the elements that you have
Make a list, one for the right side and another for the left side
Then add coefficients to the elements to the right or left side to balance out the equation

8 0

3 years ago

(select all that apply.) the elements most often found in organic molecules are _____.

Arturiano [62]

<span>C. Carbon. H. Hydrogen. N. Nitrogen. O. Oxygen. P. Phosphorus. <span>S. Sulfur.</span></span>

7 0

2 years ago

Read 2 more answers

When 15.3 g of sodium nitrate, NaNO3,was dissolved in water in a calorimeter, the temperature fell from 25.00oC to 21.56oC. If t

satela [25.4K]

Answer:

20.468 kilo Joules is the enthalpy change when one mole of sodium nitrate dissolves.

Explanation:

Heat lost by solution ad calorimeter = Q

Heat capacity of solution ad calorimeter = C = 1071 J/°C

Change in temperature = ΔT = 21.56°C - 25.00°C = -3.44°C

$Q=C\times Delta T$

$Q=1071 J/^oC\times (-3.44^oC)=-3,684.24 J$

Heat gained by sodium nitrate = -Q = -(-3,684.24 J)=3,684.24 J

Moles of sodium nitrate = $\frac{15.3 g}{85 g/mol}=0.18 mol$

When 0.18 mole of sodium nitrate was dissolved in water 3,684.24 joulesof heat was absorbed by it.

Then heat absorbed by 1 mole of sodium nitrate :

$\frac{3,684.24 J}{0.18}=20,468 J=20.468 kJ$

1 J = 0.001 kJ

20.468 kilo Joules is the enthalpy change when one mole of sodium nitrate dissolves.

8 0

3 years ago

A saline solution similar to that used for intravenous drips is made by dissolving 0.45 g sodium chloride in 50.00 g water. Whic

beks73 [17]

Answer:

E) 1, 2, and 3

Explanation:

50g H2O + 0.45g NaCl --> 50.45g saline solution

7 0

3 years ago