Answer:
Study information related to the Cenozoic era
Explanation:
Answer:
Study information related to the Cenozoic era
Explanation:
Eocene can be categorized as early epochs, It comes after the Paleocene Epoch and precedes the Oligocene Epoch. Eocene got it's origin from the Greek eos meaning ( Dawn). The beginning of Eocene produce the two appearance of two new groups of animals among the terrestrial vertebrates which are; the artiodactyls and the perissodactyls.
Eocene Epoch is reffered to as the second epoch in the order of the division of Cenozoic period . therefore, there is need for scientist to study information related to the Cenozoic era in other to know the geological time scale Eocene belongs to.
We have to first write a balanced equation.
so2 + o2 -> so3
this is not balanced though. we have 3 oxygen on right and 4 on left
2so2 + o2 -> 2so3
now it is same on both sides. we have to figure out which is limiting reagent with the given amounts of reagents. we do this by comparing the ratio between them in terms of moles. we see that so2 has a coefficient of 2 and o2 has none which implies 1 and so3 has 2. this means that for every 2 moles of so2 reacting with 1 mole of o2, we get 2 moles of so3.
lets convert the given values to moles. to do this we know that molecular weight is measured in grams per mole. we are given grams and need to cancel out the grams to get moles. so the molecular weight:
so2 =32.1 + 2 * 16 = 64.1 g/mol
o2 = 2 * 16 = 32 g/mol
so3 = 32.1 + 3 * 16 = 80.1 g/mol
now to convert 90 g of 2so2 under ideal conditions.
90g / 64.1g/mol = 1.404 moles
convert this amount of moles of so2 to moles of o2. we have 2 moles of so2 to 1 of o2
1.404moles so2 / 2 moles so2 * 1 mole o2= 0.702 moles o2
so we see under ideal conditions that 90g of so2 would react with .702g of o2. lets see how many we actually have with 100g of o2
100g / 32g/mol =3.16 mol.
so we have a lot more o2 than needed. we are looking for how much is left in grams. we have to figure out how much was used. to do this convert our ideal moles of o2 into grams.
.702 moles o2 * 32g/mol = 22.5g o2
so what we startrd with (100g) minus what we needed (22.5g) is what we have left
100 - 22.5 = 77.5g o2
The answer is (3) hydrogen ions as the only positive ions in solution. One ionic compound must have positive ion and negative ion at the same time. The Arrhenius base has hydroxyl ion as only negative ions in solution.
Answer:
the reported molar concentration of the sodium hydroxide solution will be too high.
Explanation:
The term "standardization" in science or in analytical Chemistry simply means the process involved in the determination of a standard or the concentration of a particular substance.
One of the advantages and the most important of the advantages of Standardization is that it Helps in making sure that we get a result with the least error.
So, let me explain the answer. The reported molar concentration of the sodium hydroxide solution will be TOO HIGH because the potassium hydrogen phthalate is NOT completely dry. The weight of the moisture will create an additional weight which will increase the weight of potassium hydrogen phthalate in the solution
Answer:
give us something else to work with or this is just the best guess
