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3 years ago

Determine the length of the object shown. 5.6 cm 5.60 cm 5.600 cm 6 cm

Chemistry

2 answers:

larisa [96]3 years ago

8 0

It's 5.6 cm . Hope this helps!

Nataly [62]3 years ago

5 0

Salutations!

Determine the length of the object shown below.

The length of the scale is 5.6 cm.

Hope I helped.

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In a test of an automobile engine 1.00 L of octane (702 g) is burned, but only 1.84 kg of carbon dioxide is produced. What is th

Reptile [31]

Answer:

The % yield of CO2 is 85.05 %

Explanation:

Step 1: Data given

Mass of octane = 702 grams

Molar mass octane = 114.23 g/mol

Mass CO2 =1.84 kg = 1840 grams

Molar mass of CO2

Step 2: The balanced equation

2C8H18 + 25O2 → 16CO2 + 18H2O

Step 3: Calculate moles of octane

Moles octane = mass octane / molar mass octane

Moles octane = 702.0 grams / 114.23 g/mol

Moles octane = 6.145 moles

Step 4: Calculate moles of CO2

For 2 moles octane we need 25 moles O2 to produce 16 moles CO2 and 18 moles H2O

For 6.145 moles octane we'll have 8*6.145 moles =49.16 moles

Step 5: Calculate mass of CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 49.16 moles * 44.01 g/mol

Mass CO2 = 2163.5 grams

Step 6: Calculate % yield of carbon dioxide

% yield = (actual yield / theoretical yield)*100%

% yield = (1840/2163.5)*100%

% yield = 85.05 %

The % yield of CO2 is 85.05 %

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Complete the equation for the reaction of sulfuric acid and sugar (sucrose). C12H22O11 + 11 H2SO4 ? 12 + 11 H2SO4 + 11

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Answer :

The complete equation for the reaction of sulfuric acid and sugar is,

$C_{12}H_{22}O_{11}+11 H_2SO_4\rightarrow 12C+11H_2SO_4+11H_2O$

By the stoichiometry of the reaction,

1 mole of sucrose react with the 11 moles of sulfuric acid to give 12 moles of carbon and 11 moles of water.

In this reaction, sulfuric acid react with sucrose (sugar). It dehydrates the sugar molecules which means it eliminates the water.

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Answer:

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Applying Boyle's law

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