1. The answer is option E, that is None of the above is correct. 
As a polymer becomes more crystalline,
 its melting point doesn't decreases, its density doesn't decreases, its stiffness doesn't decreases and its yield stress doesn't decreases.
 2. The answer is option B, that is the molecules are arranged in sheets, with their long axes parallel and their ends aligned as well.
In the smectic A liquid-crystalline phase, molecules are arranged in sheets, with their long axes parallel and their ends aligned as well.
3.  For a substitutional alloy to form, the two metals combined must have similar atomic radii and chemical bonding properties.
 
        
             
        
        
        
Answer:
Homeostasis is the tendency to resist change in order to maintain a stable, relatively constant internal environment. Homeostasis typically involves negative feedback loops that counteract changes of various properties from their target values, known as set points.
Explanation:
So D. Glad to help! :D
 
        
                    
             
        
        
        
What name should be used for the ionic compound
LiI?
The name that should be used for
the ionic compound LiI is Lithium iodide. When naming ionic compounds, you have
to take into consideration pairing of two components. 
 
        
                    
             
        
        
        
Answer:
the solubility increases
Explanation:
The solubility of any ionic compound is due to the ionization of the compound and then the strong ion-dipole interactions acting between the ions and the solvent.
Thus, solubility also depends on the extent of the ionization of the salt. 
The more the salt ionizes, the more there is ion-dipole interaction between the ions the solvent and more is the solubility.
 
        
             
        
        
        
Answer:
35.75 days
Explanation:
From the given information:
For first-order kinetics, the rate law can be expressed as:

Given that:
the rate degradation constant = 0.12 / day
current concentration C = 0.05 mg/L
initial concentration C₀ = 3.65 mg/L

㏑(0.01369863014) = -(0.12) t
-4.29 = -(0.12)
t = -4.29/-0.12
t = 35.75 days