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Answer:
.
Explanation:
In a projectile motion, the kinetic energy (KE) of the projectile is converted to gravitational potential energy (GPE) and then from GPE back to KE.
In this example, the spring toy is the projectile. Refer to the diagram attached.
- The spring toy started with a velocity of
, meaning that its initial KE is non-zero. - On the way up, the KE of this spring toy gets converted to GPE.
- At the top of the trajectory, the GPE of this toy is maximized while its KE is minimized (zero).
- As the toy returns to the ground, the GPE of this toy gets converted back to KE.
- The GPE of this toy is zero when the toy is on the ground.
In other words, the kinetic energy (KE) of this toy would be 
when it is at the top of the trajectory and GPE is maximized.
Since the KE of this toy at the top of the trajectory would be , the velocity of this toy at that moment would also be 
.
Answer:
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Answer:
The options are not shown, so let's derive the relationship.
For an object that is at a height H above the ground, and is not moving, the potential energy will be:
U = m*g*H
where m is the mass of the object, and g is the gravitational acceleration.
Now, the kinetic energy of an object can be written as:
K = (1/2)*m*v^2
where v is the velocity.
Now, when we drop the object, the potential energy begins to transform into kinetic energy, and by the conservation of the energy, by the moment that H is equal to zero (So the potential energy is zero) all the initial potential energy must now be converted into kinetic energy.
Uinitial = Kfinal.
m*g*H = (1/2)*m*v^2
v^2 = 2*g*H
v = √(2*g*H)
So we expressed the final velocity (the velocity at which the object impacts the ground) in terms of the height, H.
Answer:
The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other. If one of the masses is doubled, the force of gravity between the objects is doubled. increases, the force of gravity decreases
