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wlad13 [49]
2 years ago
14

What is the mass of 5.35 mol of magnesium, Mg?

Chemistry
1 answer:
Hatshy [7]2 years ago
3 0
130.03175 g. Mol to mass is multiplication. So multiply 5.35 by 24.305 and you will get the answer
You might be interested in
Given 40 grams of magnesium. How many mole is this
Dahasolnce [82]

To determine the moles in 40 grams of magnesium, we need the atomic weight. This can easily be found on a periodic table. For this problem, let's use 24.305 grams/mole.

We are going to set up an equation to determine this problem. In this equation, we want all our units to cancel out except for 'moles.'

\frac{40 g Mg}{1} x\frac{1 mole Mg}{24.305 g Mg}

In this, we can see that the unit 'grams' will cancel out to leave us with moles.

In solving the equation, we determine that there are approximately 1.65 moles of Magnesium.

3 0
3 years ago
While finding the number of molecules of oxygen molecules present in 3.65 moles of Na2SO4 the conversion factor used would be
zvonat [6]

Answer

Avogadro's number: One mole of any substance contains 6.022×10²³ molecules

Explanation

While finding the number of moles of oxygen molecules present in 3.65 moles of Na2SO4 the conversion factor used would be Avodagro's number, which is

One mole of any substance contains 6.022×10²³ molecules.

8 0
1 year ago
Describe what happens in the cell before the chemical reaction.
Zina [86]

___________________________________________________________

Answer:

Chemical reactions that take place inside living things are called biochemical reactions. The sum of all the biochemical reactions in an organism is referred to as metabolism. Metabolism includes both exothermic (heat-releasing) chemical reactions and endothermic (heat-absorbing) chemical reactions.

___________________________________________________________

6 0
2 years ago
Help needed ASAP, I will mark your answer as brainliest.
evablogger [386]

Answer:

b

Explanation:

b

4 0
3 years ago
Read 2 more answers
9. At equilibrium a 2 L vessel contains 0.360
klio [65]

Answer:

Ke = 34570.707

Explanation:

  • H2(g) + Br2(g) → 2 HBr(g)

equilibrium constant (Ke):

⇒ Ke = [HBr]² / [Br2] [H2]

∴ [HBr] = (37.0 mol) / (2 L) = 18.5 mol/L

∴ [Br2] = (0.110 mol) / (2 L) = 0.055 mol/L

∴ [H2] = (0.360 mol) / (2 L) = 0.18 mol/L

⇒ Ke = (18.5 mol/L)² / (0.055 mol/L)(0.18 mol/L)

⇒ Ke = 34570.707

3 0
3 years ago
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