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Nataliya [291]
2 years ago
12

In each term equation below a blank line shows one term missing the terms may be an elemental symbol a coefficient or a subscrip

t decide which term would balance the equation write the missing term in the second column the. Determine the reactants third column and products forth column of the reaction some reactions may have only one reactant or product and other reactions may have only one reactant or product and other reactions may have multiple reactants or products write your answers in the spaces in the table the first reaction involves sodium chloride not sodium carbon and iodine

Chemistry
1 answer:
Harlamova29_29 [7]2 years ago
7 0

Answer:

1) Cl2   2 is missing

2) H     H is missing

Explanation:

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A student ran the following reaction in the laboratory at 311 K:CH4(g) + CCl4(g) 2CH2Cl2(g)When she introduced 4.10×10-2 moles o
statuscvo [17]

<u>Answer:</u> The value of K_{eq} is 0.044

<u>Explanation:</u>

We are given:

Initial moles of methane = 4.10\times 10^{-2}mol=0.0410moles

Initial moles of carbon tetrachloride = 6.51\times 10^{-2}mol=0.0651moles

Volume of the container = 1.00 L

Concentration of a substance is calculated by:

\text{Concentration}=\frac{\text{Number of moles}}{\text{Volume}}

So, concentration of methane = \frac{0.0410}{1.00}=0.0410M

Concentration of carbon tetrachloride = \frac{0.0651}{1.00}=0.0651M

The given chemical equation follows:

                    CH_4(g)+CCl_4(g)\rightleftharpoons 2CH_2Cl_2(g)

<u>Initial:</u>          0.0410    0.0651

<u>At eqllm:</u>     0.0410-x   0.0651-x       2x

We are given:

Equilibrium concentration of carbon tetrachloride = 6.02\times 10^{-2}M=0.0602M

Evaluating the value of 'x', we get:

\Rightarrow (0.0651-x)=0.0602\\\\\Rightarrow x=0.0049M

Now, equilibrium concentration of methane = 0.0410-x=[0.0410-0.0049]=0.0361M

Equilibrium concentration of CH_2Cl_2=2x=[2\times 0.0049]=0.0098M

The expression of K_{eq} for the above reaction follows:

K_{eq}=\frac{[CH_2Cl_2]^2}{[CH_4]\times [CCl_4]}

Putting values in above expression, we get:

K_{eq}=\frac{(0.0098)^2}{0.0361\times 0.0603}\\\\K_{eq}=0.044

Hence, the value of K_{eq} is 0.044

8 0
3 years ago
How many bromine atoms are present in 39.0 g of ch2br2?
Mandarinka [93]
Answer is: there is  2,69·10²³ atoms of bromine.
m(CH₂Br₂) = 39,0 g.
n(CH₂Br₂) = m(CH₂Br₂) ÷ M(CH₂Br₂).
n(CH₂Br₂) = 39 g ÷ 173,83 g/mol.
n(CH₂Br₂) = 0,224 mol.
In one molecule of CH₂Br₂, there is two bromine atoms, so:
n(CH₂Br₂) : n(Br) = 1 : 2.
n(Br) = 0,448 mol.
N(Br) = n(Br) · Na.
N(Br) = 0,448 mol · 6,022·10²³ 1/mol.
n(Br) = 2,69·10²³.
7 0
3 years ago
Define alkylenes and alkanes​
lawyer [7]

Answer:

Alkylenes: any of the series of unsaturated hydrocarbons containing a triple bond, including acetylene.

alkanes​: Alkanes are organic compounds that consist entirely of single-bonded carbon and hydrogen atoms and lack any other functional groups. Alkanes have the general formula CnH2n+2 and can be subdivided into the following three groups: the linear straight-chain alkanes, branched alkanes, and cycloalkanes.

Explanation:

8 0
3 years ago
8.3 miles of sodium chloride in 0.65 of water.
Allisa [31]

Answer:

12.77 M

Explanation:

8.3 moles of NaCl in .65 L of water ?    Looking for M ?

8.3 M / .65 L  =  12.77 M

4 0
2 years ago
Can somebody help me with these 2 things. I honestly just need the acids and bases for both
pochemuha

Answer:

The Bronsted-Lowery acid is H2O

The Bronsted-Lowery base is CO3

The conjugate acid is HCO3

The conjugate base is OH

Explanation:

Molocules that lose a hydrogen in a reaction act as an acid, and those that recieve one act as a base.

8 0
3 years ago
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