The balanced reaction that describes the reaction of chlorine gas and sodium iodide to produce elemental iodine and sodium chloride in aqueous solution is expressed Cl2+2NaI= I2 + 2NaCl. This kind of reaction is called single replacement reaction where the anion, in this case, is only replaced
I believe it is 6ml because you do the doseage times the ml and mutiply it by 1
Explanation:
As a neutral lithium atom contains 3 protons and its elemental charge is given as
. Hence, we will calculate its number of moles as follows.
Moles = ![\frac{mass}{\text{molar mass}}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7B%5Ctext%7Bmolar%20mass%7D%7D)
= ![\frac{0.7 \times 1000 g}{7 g/mol}](https://tex.z-dn.net/?f=%5Cfrac%7B0.7%20%5Ctimes%201000%20g%7D%7B7%20g%2Fmol%7D)
= 100 mol
According to mole concept, there are
atoms present in 1 mole. So, in 100 mol we will calculate the number of atoms as follows.
No. of atoms = ![100 \times 6.023 \times 10^{23}](https://tex.z-dn.net/?f=100%20%5Ctimes%206.023%20%5Ctimes%2010%5E%7B23%7D)
=
atoms
Since, it is given that charge on 1 atom is as follows.
![3 \times 1.602 \times 10^{-19}C](https://tex.z-dn.net/?f=3%20%5Ctimes%201.602%20%5Ctimes%2010%5E%7B-19%7DC)
= ![4.806 \times 10^{-19}C](https://tex.z-dn.net/?f=4.806%20%5Ctimes%2010%5E%7B-19%7DC)
Therefore, charge present on
atoms will be calculated as follows.
![28.95 \times 10^{6}C](https://tex.z-dn.net/?f=28.95%20%5Ctimes%2010%5E%7B6%7DC)
Thus, we can conclude that a positive charge of
is in 0.7 kg of lithium.