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3 years ago

How many grams of Sn will be created when 114 grams of SnO2 react with excess H2? SnO2 + H2 ->Sn + H2O

Chemistry

1 answer:

Snezhnost [94]3 years ago

5 0

Explanation:

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Which characteristic of a strong acid

olga nikolaevna [1]

Answer:

Strong acid breaks up into ions

Explanation:

7 0

3 years ago

La masa de una olla es de 300g y contiene 90% de aluminio. Hallar el número de moles de aluminio de la olla. P.A.(Al= 27)

Neko [114]

Explanation:

The mass of a pot is 300g and contains 90% aluminum. Find the number of moles of aluminum in the pot. P.A. (Al = 27)

The mass of aluminum present in the pot is:

$300 g * 90/100\\=270 g$

Hence, in the given pot 270g Al is present.

$Number of moles of Al=\frac{given mass ofAl}{its molar mass}$

The gram atomic mass of Al -27 g/mol

Given the mass of Al is 270 g

Substitute these values in the above formula:

$Number of moles of Al=\frac{given mass ofAl}{its molar mass}\\=\frac{270 g}{27 g} \\=10.0 mol$

Answer is 10.0 mol of Al is present.

6 0

3 years ago

A sample of nitrogen gas, (N2), occupies 45.0 mL at 27.00∘C and 80.0 kPa. What will be the pressure if the gas is cooled to −73.

maxonik [38]

Answer:

The new pressure is 53.3 kPa

Explanation:

This problem can be solved by this law. when the volume remains constant, pressure changes directly proportional as the Aboslute T° is modified.

T° increase → Pressure increase

T° decrease → Pressure decrease

In this case, temperature was really decreased. So the pressure must be lower.

P₁ / T₁ = P₂ / T₂

80 kPa / 300K = P₂/200K

(80 kPa / 300K) . 200 K = P₂ → 53.3 kPa

6 0

3 years ago

Acetone is the main chemical in nail polish and has a density of 0.7857 g/mL. What is the volume of 6.54g of acetone ?

trapecia [35]

8.3mL

Explanation:

Given parameters:

Mass of acetone = 6.54g

Density of acetone = 0.7857 g/mL

Unknown:

Volume of acetone = ?

Solution:

Density is defined as the mass per unit volume of a substance. It is expressed mathematically as shown below:

Density = $\frac{Mass}{Volume}$

Since the unknown is volume, we make it the subject of the formula

Volume = $\frac{mass}{density}$

Input the values;

Volume = $\frac{6.54}{0.7857}$ = 8.3mL

learn more:

Volume brainly.com/question/2690299

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5 0

3 years ago

Calculate the amount of oxygen gas collected by the displacement of water at 14◦C if the atmospheric pressure is 790 Torr and th

zhannawk [14.2K]

Answer : The amount of oxygen gas collected are, 0.217 mol

Explanation :

Using ideal gas equation :

$PV=nRT$

where,

P = pressure of gas = $(790-12)torr=778torr=1.02atm$ (1 atm = 760 torr)

V = volume of gas = 5 L

T = temperature of gas = $14^oC=273+14=287K$

n = number of moles of gas = ?

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

$(1.02atm)\times (5L)=n\times (0.0821L.atm/mol.K)\times (287K)$

$n=0.217mole$

Thus, the amount of oxygen gas collected are, 0.217 mol

8 0

3 years ago