Vector is perpendicular to x axis or i component.
Hence i component is 0
j component is 63.5
Answer:
The impulse exerted by one cart on the other has a magnitude of 4 N.s.
Explanation:
Given;
mass of the first cart, m₁ = 2 kg
initial speed of the first car, u₁ = 3 m/s
mass of the second cart, m₂ = 4 kg
initial speed of the second cart, u₂ = 0
Let the final speed of both carts = v, since they stick together after collision.
Apply the principle of conservation of momentum to determine v
m₁u₁ + m₂u₂ = v(m₁ + m₂)
2 x 3 + 0 = v(2 + 4)
6 = 6v
v = 1 m/s
Impulse is given by;
I = ft = mΔv = m(
The impulse exerted by the first cart on the second cart is given;
I = 2 (3 -1 )
I = 4 N.s
The impulse exerted by the second cart on the first cart is given;
I = 4(0-1)
I = - 4 N.s (equal in magnitude but opposite in direction to the impulse exerted by the first).
Therefore, the impulse exerted by one cart on the other has a magnitude of 4 N.s.
soil i think is this from apex?
Answer:
E.)none of the above
Explanation:
Elastic energy = kinetic energy
½ kx² = ½ mv²
v = x √(k / m)
v = 0.2 m √(20 N/m / 2 kg)
v = 0.632 m/s
Time to travel 2.0 m:
t = (2.0 m) / (0.632 m/s)
t = 3.16 s
The resistance of wire B will be D. 1/2R
<h3>What is resistance?</h3>
It should be noted that resistance simply means the measure of the opposition to the current flow that's in an electric circuit.
Based on the information given, the resistance will be calculated thus:
= 2L/4A
= 1/2pL/A
= R/2
Therefore, the resistance of wire B will be D. 1/2R
Learn more about resistance in:
brainly.com/question/24858512
#SPJ4
Two wires A and B with circular cross sections are made of the same metal and have equal lengths, but the resistance of wire A is three times greater than that of wire B. (ii) What is the ratio of the radius of A to that of B
(a) 4 R (b) 2 R (c) R (d) 1/2R (e) 1/4R
