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Fed [463]
3 years ago
11

Calculate the power transfer when a pump moves 50kg of water through a vertical height of 8meters in 5seconds (take g =10meters

per second)​
Physics
1 answer:
Vika [28.1K]3 years ago
4 0

Hi there!

Recall the following relationships:

W = \Delta U = mg\Delta h\\\\P = \frac{W}{t}

W = Work (J)

U = Potential Energy (J)

m = mass (kg)

g = acceleration due to gravity (9.8 m/s²)

h = height (m)

t = time (s)

Begin by calculating the work:

W = 50(10)(8) = 4000 J

Now, divide by the time to solve for power:

P = \frac{4000}{5} = \boxed{800W}

**W is the unit for power (Watts).  Be careful not to get the two confused.

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The cart is given an initial push up the ramp. After this push, as the car moves up the ramp, the direction of the acceleration
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Answer:

Explanation:

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Even when the cart is moving up after the initial push , its weight is acting downwards so acceleration is acting downwards .

When the cart is stationary at the top position , its weight is acting downwards so acceleration is downwards at that moment also . When the cart is going downwards , still its weight is acting down so acceleration is acting downwards .

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3 0
3 years ago
Calculate the kinetic energy of a truck that has a mass of 2400kg and is moving at 15m/s
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Answer:

Given,

Explanation:

mass(m)=2400kg

velocity(v)=15m/s

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3 years ago
All of the following are factors affecting flow rate except what?
faust18 [17]

Answer:

c. Vessel side holes

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  • The "Poiseuille formula" which is given by \\\begin{aligned} \small Q& =  \small \frac{\pi r^4}{8 \eta}.\frac{\Delta P}{\Delta L}\\\end{aligned} describes the volumetric flow rate (\small Q) through tubular sections.
  • Here, \Delta P,\,\, \Delta L,\,\, r,\,\, \eta represent the injection pressure difference, the length of the section, the radius of the section and the viscosity index of the fluid that flows through the section respectively.
  • With this, one can confirm that all the factors except the vessel side holes affect the flow rate.
  • Side holes, however, are a factor that could give a measure of how much volume would flow to a particular location. In such a situation the flow rate remains unchanged and one location would receive a lower volume (not the whole) as some volume would spill out at the side holes.

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2 years ago
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