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kati45 [8]
2 years ago
11

3. How many grams of water will be produced from 15.0 grams of Methane? * CH4 +2 02 → CO2 + 2H2O

Chemistry
1 answer:
jok3333 [9.3K]2 years ago
8 0
CH4 + 2O2 = CO2 + 2H2O

According to molar weights :

16 gm CH4 + 64 gm O2 = 44 gm CO2 + 36 gm H2O

Since 16 gm CH4 produce 36 gm H2O

Hence 2.5 gmCH4 produce 36×2.5/16 gm H2O

= 5.265 gm of H2O
2.1K viewsView 2 Upvoters

2



1

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I'm pretty sure number 48 is C. Hope this helped :)
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A sample of copper metal has a mass of 848 grams. How many moles of copper are in the sample? 13.34 mol Cu, 13.3 mol Cu, 12.9 mo
ANTONII [103]

Answer:

mol_{Cu}=13.34molCu

Explanation:

Hello,

In this case, as the atomic mass of coppe is 63.546 g/mol, with the given mass with can compute the moles as shown below:

mol_{Cu}=848gCu*\frac{1molCu}{63.546 gCu} \\\\mol_{Cu}=13.34molCu

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5. The reaction of magnesium oxide with hydrochloric acid carried out in a calorimeter caused the
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Answer:

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Explanation:

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An unknown amount of acid can often be determined by adding an excess of base and then back-titrating the excess. A 0.3471−g sam
MAXImum [283]

Explanation:

The given data is as follows.

       Mass of mixture = 0.3471 g

As the mixture contains oxalic acid and benzoic acid. So, oxalic acid will have two protons and benzoic acid has one proton.

This means oxalic acid will react with 2 moles of NaOH and benzoic acid will react with 1 mole of NaOH.

Hence,   moles of NaOH in 97 ml = \frac{0.1090 \times 97}{1000}

                                                       = 10.573 \times 10^{-3} mol

Moles of HCl in 21.00 ml = \frac{0.2060 \times 21}{1000}

                                         = 4.326 \times 10^{-3} mol

Therefore, total moles of NaOH that reacted are as follows.

           10.573 \times 10^{-3} mol - 4.326 \times 10^{-3} mol      

                = 6.247 \times 10^{-3} mol

So, total 3 mole of NaOH will react with 1 mole of mixture. Therefore, number of moles of NaOH reacted with benzoic acid is as follows.

                  \frac{6.247 \times 10^{-3}}{3}

                    = 2.082 \times 10^{-3} mol

Since, molar mass of NaOH is 40 g/mol. Therefore, calculate the mass of NaOH as follows.

                    2.082 \times 10^{-3} mol \times 40 g/mol

                         = 83.293 \times 10^{-3} g

                         = 0.0832 g

Whereas molar mass of benzoic acid is 122 g/mol.

Therefore,       40 g NaOH = 122 g benzoic acid

So,            0.0832 g NaOH = \frac{122 g}{40 g} \times 0.0832 g

                                             = 0.253 g

Hence, calculate the % mass of benzoic acid as follows.

                      \frac{0.253 g}{0.3471 g} \times 100

                           = 73.10%

Thus, we can conclude that mass % of benzoic acid is 73.10%.

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3 years ago
Why does opening the air valve of a tire at a constant temperature decrease the pressure
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The number of molecules decrease
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