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2 years ago

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3. How many grams of water will be produced from 15.0 grams of Methane? * CH4 +2 02 → CO2 + 2H2O

1 answer:

jok3333 [9.3K]2 years ago

8 0

CH4 + 2O2 = CO2 + 2H2O

According to molar weights :

16 gm CH4 + 64 gm O2 = 44 gm CO2 + 36 gm H2O

Since 16 gm CH4 produce 36 gm H2O

Hence 2.5 gmCH4 produce 36×2.5/16 gm H2O

= 5.265 gm of H2O
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ANTONII [103]

Answer:

$mol_{Cu}=13.34molCu$

Explanation:

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In this case, as the atomic mass of coppe is 63.546 g/mol, with the given mass with can compute the moles as shown below:

$mol_{Cu}=848gCu*\frac{1molCu}{63.546 gCu} \\\\mol_{Cu}=13.34molCu$

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An unknown amount of acid can often be determined by adding an excess of base and then back-titrating the excess. A 0.3471−g sam

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Explanation:

The given data is as follows.

Mass of mixture = 0.3471 g

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This means oxalic acid will react with 2 moles of NaOH and benzoic acid will react with 1 mole of NaOH.

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$\frac{6.247 \times 10^{-3}}{3}$

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$2.082 \times 10^{-3} mol \times 40 g/mol$

= $83.293 \times 10^{-3}$ g

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Therefore, 40 g NaOH = 122 g benzoic acid

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= 0.253 g

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$\frac{0.253 g}{0.3471 g} \times 100$

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