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Zarrin [17]
3 years ago
15

Um...id.k how to do chemistry...help please?

Chemistry
2 answers:
Cerrena [4.2K]3 years ago
4 0

Answer:

um...id.k how to do chemistry...help please?

Explanation:

NaBr

qaws [65]3 years ago
3 0

Answer:

NaBr

Explanation:

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3 0
3 years ago
How do I balance a chemical reaction like one of these NaBr + Ca(OH)2 ➡️ CaBr2 + NaOH
mojhsa [17]
2NaBr + Ca(OH)2 ➡️ CaBr2 + 2NaOH
3 0
3 years ago
If the reaction N2 (g) + 3 H2 (g) --&gt; 2 NH3 (g) has the concentrations 1.1 M for nitrogen, 0.75 M for hydrogen and 0.25 M fo
Luba_88 [7]

<u>Answer:</u> The value of K_c is 0.136 and is reactant favored.

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For the chemical reaction between carbon monoxide and hydrogen follows the equation:

N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

The expression for the K_{c} is given as:

K_{c}=\frac{[NH_3]^2}{[N_2][H_2]^3}

We are given:

[NH_3]=0.25M

[H_2]=0.75M

[N_2]=1.1M

Putting values in above equation, we get:

K_c=\frac{(0.25)^2}{1.1\times (0.75)^3}

K_c=0.135

There are 3 conditions:

  • When K_{c}>1; the reaction is product favored.
  • When K_{c}; the reaction is reactant favored.
  • When K_{c}=1; the reaction is in equilibrium.

For the given reaction, the value of K_c is less than 1. Thus, the reaction is reactant favored.

Hence, the value of K_c is 0.136 and is reactant favored.

4 0
3 years ago
If the empirical formula of a compound is CH2, which of the following could be a possible molecular formula for this
DiKsa [7]

Answer:

C2H2

Explanation:

8 0
3 years ago
15 POINTS PLEASE HELP
Lapatulllka [165]

Answer:

Neutrons = ( Atomic mass – Atomic number ) ( A–Z )

Protons and Electrons are equal to the atomic number

For example Neon,

Mass number (A) = 20

Atomic Number (Z) = 10

Number of Protons = 10

Number of Electrons = 10

Number of Neutrons = ( A–Z ) = 10

Electronic distribution :

K= 2

L= 8

4 0
3 years ago
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