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riadik2000 [5.3K]
3 years ago
14

Equal amounts of four gases are placed in identical containers at the temperatures that are noted below. Samples of Gases at Dif

ferent Temperatures Gas Temperature (°
c. P 10.2 Q 25.4 R 25.9 S 33.2 Molecules of which gas would exert the greatest collision force?
Chemistry
1 answer:
Alborosie3 years ago
4 0
Answer : S)  33.2 °C

Explanation : When the equal amounts of gases are placed in identical containers but subjected to different temperatures would exert pressure in different amount which will in turn increase the rate of collision between the molecules of gas.

So, when the temperature is increased to maximum greater amount of force would be exerted and the gas molecules will collide with a larger force. Hence the answer will be as the highest temperature i.e. 33.2 °C
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Explanation:

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What happens when the temperature of a solid reaches it’s melting point
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2 years ago
a metal object has a mass of 9.0g and a volume of 1.5ml. what is the density of the object? density= mass/volume​
weeeeeb [17]

The density of the metal object=6.0\frac{g}{m l}

Given:

Volume of the metal object=1.5ml

Mass of the metal object=9.0g

To find:

Density of the metal object

<u>Step by Step Explanation: </u>

Solution:

According to the formula, Density of the metal object can be calculated as

\rho=\frac{m}{v}

Where, m=mass of the metal object

\rho =density of the metal object

v=volume of the metal object

We know the values of v=1.5ml and m=9.0g

Substitute these values in the above equation we get

\rho=\frac{m}{v}

\rho=9.0/1.5

=6.0\frac{g}{m l}

Result:

Thus the density of the metal object is 6.0\frac{g}{m l}

4 0
3 years ago
Plz help i need the answer ASAP If 6.20 cm3 of a 6.75 M (M = mol/dm3) solution are diluted to 85.6 cm3 with water, what is the c
Brilliant_brown [7]

Answer:

Option A. 6.75 (6.20/85.6)

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 6.2cm³

Initial concentration (C1) = 6.75M

Final volume (V2) = 85.6cm³

Final concentration (C2) =.?

The final concentration can be obtained by using the dilution formula as show below:

C1V1 = C2V2

6.75 x 6.2 = C2 x 85.6

Divide both side by 85.6

C2 = (6.75 x 6.2) /85.6

C2 = 6.75 (6.2 / 85.6).

6 0
3 years ago
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