1) velocity: 98 m/s downward
Explanation:
The marble moves by uniformly accelerated motion, with constant acceleration a=g=-9.8 m/s^2 directed towards the ground. Therefore, its velocity at time t is given by:
where
is the initial velocity
is the acceleration
is the time
Substituting t = 10 s, we find:
And the negative sign means the direction of the velocity is downward.
2) Distance covered: 490 m
The distance covered in an uniformly accelerated motion can be found with the formula:
where
is the acceleration
t is the time
Substituting t=10 s, we find
And the negative sign means the displacement is below the dropping point.
It should be the third row,
as input is chemical (fuel) and heat(thermal) is wasted
The question isn't clear enough, I think it ask us to calculate the linear speed of a point at the edge of the DVD.
Now let's imagine we're a point at the edge of the DVD, we're undergoing a circular motion. Each minute we will complete a circular track 7200 times, now we need to know the distance we travel each turn. The perimeter of the DVD, a circular object is:
Know recall that:
We now need to know how much distance is traveled during a minute or 60 seconds:
Finally we divide this result with t=60 seconds:
Where the distance units were named units as the length unit is not specified in this exercise.<span />
Answer:
the earthquake's epicenter is L = 1091.2 km away
Explanation:
if the P and S waves start from the same place (x=0) :
P would travel the distance L in , L = vP * tP
P would travel the distance L in , L = vS * tS
therefore
vP * tP= vS * tS
if the difference in time d= tS-tP → tS=d+tP , then
vS * tS= vP * tP
vS *(d+tP) = vP * tP
vS*d + vS*tP = vP * tP
vS*d = vP * tP - vS*tP = (vP - vS) * tP
tP = vS*d / (vP - vS)
replacing values
tP = vS*d / (vS - vP) = 5.1 km/s * 1.5 min*60 s/min / ( 8.8 km/s - 5.1 Km/s) = 124 s
therefore
L = vP*tP = 8.8 km/s * 124 s = 1091.2 km
It’s blurry the pic
But I think that is the second one