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3 years ago

If HCr2O7 is titrated with Ca(OH)2, what is the balanced chemical equation of this neutralization reaction?

Chemistry

1 answer:

Harrizon [31]3 years ago

6 0

Answer:

2HCr2O7(aq) + Ca(OH)2(aq) --> 2H2O(l) + Ca(Cr2O7)2

Explanation:

A neutralization reaction produces water and a salt. Since Ca(OH)2 has two hydroxides, two water molecules are produced, which means you also need two molecules of the acid. Having two molecules of the acid also ensures that you have two dichromates on both sides.

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Determine the number of bonding electrons and the number of nonbonding electrons in the structure of SI2. Enter the number of bo

mariarad [96]

Answer:

4, 16,

Explanation:

SI2 is sulphur diiodide. Sulphur is in group sixteen (six valence electrons) while iodine is in group 17(seven valence electrons).

Since there are two iodine atoms and one sulphur atom, the molecule has twenty valence electrons. Out of these twenty valence electrons, only four are bonding electrons. The other sixteen electrons include the four nonbonding electrons found on sulphur and the twelve non bonding electrons found on the two iodine atoms having six nonbonding electrons each.

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3 years ago

Increased irrigation demands: decrease the rate of transpiration increase the rate of surface water evaporation change the amoun

drek231 [11]

Answer: Increase the rate of surface water evaporation

Irrigation is a process, in which the crops are supplied with water, to ensure their proper growth. Increased in the irrigation supply can be because of the environmental conditions like hot summer season or may be because of the type of soil is semi arid or arid means the soil does not retains moisture efficiently. This will result in increase in the rate of evaporation of the surface water.

7 0

3 years ago

For the reaction: CH3NH2(aq) + H2O(aq) ⇌ CH3NH3 +(aq) + OH- Determine the change in the pH (ΔpH) for the addition of 6.7 M CH3NH

Korolek [52]

Answer:

The change in the pH (ΔpH) is 2,17

Explanation:

The reaction:

CH₃NH₂(aq) + H₂O(aq) ⇌ CH₃NH₃⁺(aq) + OH⁻

$kb = \frac{[OH^{-}][CH_{3}NH_{3}^+]}{[CH_{3}NH_{2}]}$ (1)

In equilibrium, a solution of CH₃NH₂ 4,7M produces:

[CH₃NH₂] = 4,7 - x

[CH₃NH₃⁺] = x

[OH⁻] = x

Replacing in (1):

$4,38x10^{-4} = \frac{x^2}{4,7-x}$

x² + 4,38x10⁻⁴x - 2,0586x10⁻³ = 0

The solutions are:

x = -0,0456 No physical sense. There are not negative concentrations.

x = 0,04515 Real answer.

The concentration of [OH⁻] is 0,04515 M.

As pOH = -log [OH⁻] And pH+pOH = 14. The pH of this solution is:

pH = 12,65

The addition of 6,7M produce this changes in concentrations:

[CH₃NH₂] = 4,656 + x

[CH₃NH₃⁺] = 6,74515 - x

[OH⁻] = 0,04515 - x

Replacing in (1) you will obtain:

x² - 6,7907x + 0,3025 = 0

Solving for x:

x = 6,74586 No physical sense

x = 0,04484 Real answer.

Thus, [OH⁻] = 0,04515 - 0,044842 = 3,08x10⁻⁴M

pOH = 3,51.

pH = 10,49

Thus ΔpH is 12,65 - 10,49 = 2,16 ≈ 2,17

I hope it helps!

4 0

4 years ago

What state does a maple tree enter during the winter?

Crank

D. dormancy is the correct answer

3 0

3 years ago

BRAINLIEST TO FIRST CORRECT ANSWER, THANKS!

Tamiku [17]

Answer:

increased

Explanation:

Consuming a compound increases the concentration. When you increase the concentration, the rate constant for that reaction also increases.

5 0

4 years ago