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xz_007 [3.2K]
3 years ago
6

Which electromagnetic wave has the shortest wavelength? (A. Radio waves b. X-rays c.infrared rays or d. Visible light)

Physics
1 answer:
RSB [31]3 years ago
4 0
X-rays have the shortest wavelength of any waves on that particular list.
Gamma ray waves are shorter than X-rays, but they're not on that list.
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A telephone wire has a current 20A flowing through it . How long does it take for a charge of 15 C to pass through the wire?
Sauron [17]
Charge = Current/time
Q = It
t = Q/I = 15/20 = 0.75 s
7 0
4 years ago
A uranium ion and an iron ion are separated by a distance of =61.10 nm. The uranium atom is singly ionized; the iron atom is dou
scoray [572]

Answer:

Explanation:

Charge on uranium ion = charge of a single electron

= 1.6 x 10⁻¹⁹ C

charge on doubly ionised iron atom = charge of 2 electron

= 2 x 1.6 x 10⁻¹⁹ C = 3.2 x 10⁻¹⁹ C

Let the required distance from uranium ion be d .

force on electron at distance d from uranium ion

= 9 x 10⁹ x 1.6 x 10⁻¹⁹ / r²

force on electron at distance 61.10 x 10⁻⁹ - r from iron  ion

= 9 x 10⁹ x 3.2 x 10⁻¹⁹ / (61.10 x 10⁻⁹ - r )²

For equilibrium ,

9 x 10⁹ x 1.6 x 10⁻¹⁹ / r² = 9 x 10⁹ x 3.2 x 10⁻¹⁹ / (61.10 x 10⁻⁹ - r )²

2 d² = (61.10 x 10⁻⁹ - r )²

1.414 r = 61.10 x 10⁻⁹ - r

2.414 r = 61.10 x 10⁻⁹

r = 25.31 nm .

4 0
3 years ago
Water drips from a shower head (the sprayer at the top of the shower) and falls onto the floor 2.3 m below. The droplets are fal
Maurinko [17]

Answer:

0.767m

Explanation:

We are given that the time interval between each droplet is equal.

We are also given that the fourth drop is just dripping from the shower when the first hits the floor.

If they fall at the same time interval and we know that the distance between the shower head and floor are the same, they must therefore fall at the same velocity.

The distance between each drop has to be the same given that they fall at equal time intervals.

Let this distance be x.

We can then partition the entire height of the system into three parts (as shown in the diagram).

Hence, we can say that:

x + x + x = 2.3m

3x = 2.3m

=> x = 2.3/3 = 0.767m

Therefore, at the time the first drop hits the floor, the third drop is only 0.767 m below the shower head.

8 0
3 years ago
Where does fission regularly occur and what kind of energy is produced?
WARRIOR [948]
Which one are you talking about bc there's a couple
6 0
3 years ago
Read 2 more answers
A 25 newton force applied on an object moves it 50 meters. The angle between the force and displacement is 40.0°. What is the va
zloy xaker [14]

Answer:

<em>T</em><em>he value of work being done on the object is 958J.</em>

Explanation:

<em>Work</em><em> done</em><em> </em><em>is </em><em>equal</em><em> to</em><em> </em><em>force</em><em> </em><em>multiply</em><em> by</em><em> </em><em>distance,</em><em> </em><em>but </em><em>when</em><em> </em><em>the </em><em>angle</em><em> </em><em>is </em><em>between</em><em> </em><em>the</em><em> </em><em>force</em><em> </em><em>and</em><em> </em><em>distance</em><em> </em><em>work</em><em> </em><em>done=</em><em>Force</em><em> (</em><em>cos</em><em> </em><em>theta)</em><em> </em><em>×</em><em> </em><em>distance</em>

<em>Work</em><em> done</em><em> </em><em>=</em><em> </em><em>Force(</em><em>cos </em><em>theta</em><em>)</em><em> </em><em>×</em><em> </em><em>distance</em>

<em>Work</em><em> done</em><em> </em><em>=</em><em> </em><em>2</em><em>5</em><em>N</em><em>(</em><em>cos </em><em>4</em><em>0</em><em>.</em><em>0</em><em>°</em><em>)</em><em> </em><em>×</em><em> </em><em>5</em><em>0</em><em>m</em>

<em>Work</em><em> done</em><em> </em><em>=</em><em> </em><em>2</em><em>5</em><em>N</em><em>(</em><em>0</em><em>.</em><em>7</em><em>6</em><em>6</em><em>0</em><em>)</em><em> </em><em>×</em><em> </em><em>5</em><em>0</em><em>m</em>

<em>Work</em><em> done</em><em> </em><em>=</em><em> </em><em>19.15N </em><em>×</em><em> </em><em>5</em><em>0</em><em>m</em>

<em>Work</em><em> done</em><em> </em><em>=</em><em> </em><em>957.5J </em><em>=</em><em> </em><em>9</em><em>5</em><em>8</em><em>J</em>

<em>T</em><em>herefore</em><em> the</em><em> </em><em>value</em><em> of</em><em> </em><em>work</em><em> </em><em>being</em><em> </em><em>done </em><em>on </em><em>the</em><em> </em><em>object</em><em> </em><em>is </em><em>9</em><em>5</em><em>8</em><em>J</em><em>.</em>

3 0
2 years ago
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