Answer:
a)v= 675V
b) v=-675V
c)v=-450V
Explanation:
Formula: V = k*sum(qi/ri)
Given:
q1 = +6.00nC --> R1 = 2.00cm
q2 = -9.00nC --> R2 = 4.00cm
(a) r = 0. So, inside both shells
V=675V
(b) r = 4.00cm. So, This point is outside of shell 1 but inside shell 2.
V=-675V
(c) r = 6.00cm. So, This point out of both shells.
A ) The first ball:
h = v o * t - g t² / 2
19.6 = 14.7 t + 9.8 t²/2
4.9 t² + 14.7 t - 19.6 = 0
t 1/2 = (-14.7 +/- √216.09+384.16 ) / 9.8 = 9.8/9.8 = 1 s
The second ball:
v = v o - g t
0 = 14.7 - 9.8 t
9.8 t = 14.7
t = 1.5 ( upward )
h = 19.6 + 14.7 - 9.8 * 1.5 = 30.625 m
30.625 = 9.8 * t²/2
t² = 6.25
t = 2.5 s ( downward )
1.5 s + 2.5 s = 4 s
The difference: 4 s - 1 s = 3 s.
B ) The first ball:
v = v o + g t = 14.7 + 9.8 * 1 = 24.5 m/s
The second ball:
v = g * t = 9.8 * 3 = 24.5 m/s
C ) d 1 = 14.7 * 0.8 + 9.8 * 0.8²/2 = 11.76 + 3.136 = 14.896 m
d 2 = 14.7 * 0.8 - 9.8* 0.8²/2 = 11.76 - 3.136 = 8.624 m
d 1 + d 2 = 14.896 + 8.624 = 23.52 m
Answer:
want
Explanation:
because it is not actually needed for the existence of life at that particular time
Answer:
v' = -2.5 cm/s
Explanation:
given,
mass of toy car, m = 10 g
speed of right, u= 20 cm/s
mass of toy car, M = 24 g
speed opposite, u' = 35 cm/s
after collision
10 g car moves to left, v = 58 cm/s
v' = ?
using conservation of momentum
m u + M u' = m v + M v'
10 x 20 - 24 x 35 = - 10 x 58 + 24 x v'
24 x v' = -60
v' = -2.5 cm/s
speed of second car after collision = -2.5 cm/s