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Vilka [71]
3 years ago
9

The following are possible ways to express the quantity 0.391 (Give ALL correct answers, i.e., B, AC, BCD...) Note: 3.45E-8 is a

way you can enter the number 3.45×10-8 in most computers. A) 0.000391E4 B) 39.1 x 10-1 C) 0.391E+1 D) 3.91E-1 E) 0.0391E+1 F) 0.00391 x 102
Physics
1 answer:
laiz [17]3 years ago
4 0
To answer, evaluate the power of 10 in the given choices. If it is positve, move the decimal n places to the right. If it is negative, move the decimal n corresponding places to the left. From all the choices given, only the choices D, E, and F will give us the correct answer. 
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Light of wavelength 480 nm illuminates a double slit, and the interference pattern is observed on a screen. At the position of t
vova2212 [387]

Answer:

BC =980nm

Explanation:

Given wavelength =490nm

m=2

Required to find (OB - OC) = BC (more distant slit - nearest slit ) = dsin theta

We have dsin theta = m*wavelength

or BC = m* wavelength = 2*490nm

= 980nm = 98.000A

4 0
3 years ago
How do inertia and centripetal force combine to keep an object moving in circular motion?
Aleonysh [2.5K]
<span>Centripetal force acts toward the center of the circle, and inertia keeps the object moving forward.
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7 0
3 years ago
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Spring #1 has a force constant of k, and spring #2 has a force constant of 2k. Both springs are attached to the ceiling. Identic
Gre4nikov [31]

Answer:

The ratio of the energy stored by spring #1 to that stored by spring #2 is 2:1

Explanation:

Let the weight that is hooked to two springs be w.

Spring#1:

Force constant= k

let x1 be the extension in spring#1

Therefore by balancing the forces, we get

Spring force= weight

⇒k·x1=w

⇒x1=w/k

Energy stored in a spring is given by \frac{1}{2}kx^{2} where k is the force constant and x is the extension in spring.

Therefore Energy stored in spring#1 is, \frac{1}{2}k(x1)^{2}

                                                              ⇒\frac{1}{2}k(\frac{w}{k})^{2}

                                                              ⇒\frac{w^{2}}{2k}

Spring #2:

Force constant= 2k

let x2 be the extension in spring#2

Therefore by balancing the forces, we get

Spring force= weight

⇒2k·x2=w

⇒x2=w/2k

Therefore Energy stored in spring#2 is, \frac{1}{2}2k(x2)^{2}

                                                              ⇒\frac{1}{2}2k(\frac{w}{2k})^{2}

                                                              ⇒\frac{w^{2}}{4k}

∴The ratio of the energy stored by spring #1 to that stored by spring #2 is \frac{\frac{w^{2}}{2k}}{\frac{w^{2}}{4k}}=2:1

4 0
3 years ago
ASAP
pochemuha

Answer:

Explanation:

The fish falls from vertical rest in a time of

t = √(2h/g) = √(2(2.27)/9.81) = 0.68 s

v = d/t = 5.6 / 0.68 = 8.2 m/s

4 0
3 years ago
PLEASE ASAP ILL GIVE BRAINLIEST.
Olegator [25]

Answer:

The answer is number 2 :)

8 0
3 years ago
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