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Nutka1998 [239]
3 years ago
15

A car traveling at 30 m/s north slows to a stop in 15 seconds. What is the acceleration? PLEASE HELP

Physics
2 answers:
Lapatulllka [165]3 years ago
6 0
The answer is C..........
Scilla [17]3 years ago
3 0
The "acceleration" is negative so it's a deceleration. Change of speed = 30 m/s. Time taken for change 15 seconds Deceleration 30m/s^-1 divided by 15 seconds which is 2m/s per second ...
Nice and gentle, and so not the "modern way"
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You are driving due north on i-81 to come to jmu with a speed of 10 m/s, suddenly you realize you forgot your book. You make a u
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first we make a U turn and travel towards home in t = 20 s

so the distance of home from initial position is

d_1 = v*t_1

d_1 = 10*20 = 200 m

Now after picking up the book we travel back with speed 20 m/s

so again after t = 20 s the displacement is given as

d_2 = v*t = 20*20 = 400 m

so the net displacement is given as

\vec d = \vec d_2 - \vec d_1

\vec d = 400 - 200 = 200 m

so it will be displaced by total displacement 200 m

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A person drives for 1.00 h at 10.0 km/h and 2.00 h at 20.0 km/h. What is their average speed, in SI units?
Veronika [31]
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3 years ago
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3 years ago
Find the frequency of a wave of wavelength 2.5m and speed 400 m/s
Sedaia [141]

Answer:

The frequency of wave is 160Hz.

Explanation:

Given that the formula of speed is V = f×λ where V represents speed, f is frequency and λ is wavelength.

So first thing, you have to make frequency the subject by dividing wavelength on both sides :

v = f \times λ \:

v \div  λ =  f \times λ \div λ

f =  \frac{v}{λ}

Next you have to substitute the value of v and f into the formula :

Let λ = 2.5m,

Let v = 400m/s,

f =  \frac{400}{2.5}

f = 160Hz

7 0
3 years ago
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