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2 years ago

A car traveling at 30 m/s north slows to a stop in 15 seconds. What is the acceleration? PLEASE HELP

Physics

2 answers:

Lapatulllka [165]2 years ago

6 0

The answer is C..........

Scilla [17]2 years ago

3 0

The "acceleration" is negative so it's a deceleration. Change of speed = 30 m/s. Time taken for change 15 seconds Deceleration 30m/s^-1 divided by 15 seconds which is 2m/s per second ...
Nice and gentle, and so not the "modern way"

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3 years ago

A race car has a maximum speed of 0.104 km/s .What is this speed in miles per hour ?

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Answer:

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Explanation:

A race car has a maximum speed of 0.104km/s

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2 years ago

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2 years ago

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2 years ago

A photon with an energy E = 2.12 GeV creates a proton-antiproton pair in which the proton has a kinetic energy of 96.0 MeV. What

Oksanka [162]

Answer:

The kinetic energy of the anti proton is 147.4 MeV.

Explanation:

Given that,

Energy = 2.12 GeV

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We need to calculate the kinetic energy of the anti proton

Using formula of energy

$E_{photon}=m_{p}c^2+m_{np}c^2+K.E_{p}+K.E_{np}$

We know that,

$m_{p}c^2=m_{np}c^2$

So, $E_{photon}=2mc^2+K.E_{p}+K.E_{np}$

$K.E_{np}=E_{photon}-(2mc^2+K.E_{p})$

Put the value into the formula

$K.E_{np}=2.12\times10^{9}-2\times938.3\times10^{6}-96\times10^{6}$

$K.E_{np}=147.4\ MeV$

Hence, The kinetic energy of the anti proton is 147.4 MeV.

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2 years ago