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3 years ago

Another example of a parasitic

Chemistry

1 answer:

sasho [114]3 years ago

7 0

Answer:a leech

Explanation: a parasitic relationship is one organism benefit on the other while the other is harmed

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Show the relationship of number of moles and volume in Avogadro's law using data. Write your calculations and answer on a separa

leonid [27]

Answer:

See below ~

Explanation:

The calculated values of V/n :

⇒ 1.5/0.3 = 5

⇒ 3/0.6 = 5

⇒ 4.5/0.9 = 5

⇒ 6/1.2 = 5

⇒ 7.5/1.5 = 5

1. From this we understand that the calculated values of V/n remain constant, equal to 5 in this case.

2. The volume-mole graph will be a straight line passing through the origin. (Attached below)

7 0

2 years ago

Consider the chemical equation in equilibrium.

Kruka [31]

By increasing the P reaction moves toward less number of moles in this case
The equilibrium will shift to the left to favor the reverse reaction.

4 0

3 years ago

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Triss [41]

Answer:

Explanation:

6 0

2 years ago

If is found that 24.68 mL of .1165 M NaOH is needed to titrate .2931 g of an unknown acid to the phenolphthalein end point. Calc

Lemur [1.5K]

Answer: The equivalent mass of the acid is 83.16 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}$

Molarity of $NaOH$ solution = 0.1165 M

Volume of $NaOH$ solution = 24.68 mL = 0.02468 L

Putting values in equation 1, we get:

$\text{Moles of} NaOH={0.1165M}\times{0.02468L}=2.875\times 10^{-3}moles=2.875\times 10^{-3}geq$

( as acidity of NaOH is 1)

For end point: gram equivalents of acid = gram equivalents of base = $2.875\times 10^{-3}$

Mass of acid= $gram equivalents\times {\text {Equivalent mass}}$

$0.2391=2.875\times 10^{-3}\times {\text {Equivalent mass}}$

${\text {Equivalent mass}}=83.16g$

Thus equivalent mass of the acid is 83.16 grams

5 0

3 years ago

Formulas for the compounds below. Sulfur Trioxide Sodium hydroxide

GarryVolchara [31]

Sulphur Trioxide = So3

Sodium Hydroxide = NaoH

6 0

2 years ago

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