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Sidana [21]
4 years ago
7

What is the main function of the muscular system A. digestion B. breathing C.movement D. Eliminating

Chemistry
2 answers:
Eva8 [605]4 years ago
5 0

Answer:

C, Movement

Explanation:

natita [175]4 years ago
3 0
The answer is C- movement
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President Jackson was addressing the Native American Indians
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Mercury(II) oxide (HgO) decomposes to form mercury (Hg) and oxygen (O2). The balanced chemical equation is shown below. 2HgO Rig
BigorU [14]

Taking into account the reaction stoichiometry, the correct answer is the third option: 15.63 moles of HgO are needed to produce 250 g of O₂.

In first place, the balanced reaction is:

2 HgO  → 2 Hg + O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • HgO: 2 moles
  • Hg: 2 moles
  • O₂: 1 moles  

The molar mass of the compounds is:

  • HgO: 216.59 g/mole
  • Hg: 200.59 g/mole
  • O₂: 32 g/mole  

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:  

  • HgO: 2 moles× 216.59 g/mole= 433.18 grams
  • Hg: 2 moles× 200.59 g/mole= 401.18 grams
  • O₂: 1 mole× 32 g/mole= 32 grams

Then the following rule of three can be applied: if by reaction stoichiometry 32 grams of O₂ are produced by 2 moles of HgO, 250 grams of O₂ are produced from how many moles of HgO?

moles of HgO=\frac{250 grams of O_{2} x2 moles of HgO}{32grams of O_{2}}

<u><em>moles of HgO= 15.625 moles≅ 15.63 moles</em></u>

Finally, the correct answer is the third option: 15.63 moles of HgO are needed to produce 250 g of O₂.

Learn more about reaction stoichiometry:

  • <u>brainly.com/question/24741074 </u>
  • <u>brainly.com/question/24653699 </u>
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Laser cutting provides a more precise , clean cut.

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Calculate the mass percent composition of nitrogen in co(nh2)2.
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The  mass  percentage  composition  of  nitrogen  in  CO(NH2)2  is 46 .7%

    calculation

%  mass  =   molar  mass  of nitrogen/ molar mass  of  Co(NH2)2 

molar mass  of nitrogen =  14 x2 = 28g/mol  since there is  two  nitrogen atom  in  Co(NH2)2\

molar mass  of CO(NH2)2  = 12 + 16 + (14 x2) +( 2 x2)=  60 g/mol

the %  mass  is therefore =28 /  60  x100   =46.7%
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