Question

Proposed Exercise: Conservation of the Linear Moment

Answer 1

Explanation:

Momentum is conserved when there is no net external force.  So momentum is conserved in the direction parallel to the incline.

p₀ = p

m v cos θ = (m + M) vₓ

vₓ = m v cos θ / (m + M)

After the collision, energy is conserved.

PE = KE

(m+M) gh = ½ (m+M) vₓ²

gh = ½ vₓ²

h = vₓ² / (2g)

d sin θ = [m v cos θ / (m + M)]² / (2g)

d = [m v cos θ / (m + M)]² / (2g sin θ)