Answer:
No it is not a problem
Explanation:
It is not a problem because the stress intensity factor K would approach infinity as you get close to a crack tip and the intensity factor would approach Zero as you get too far away from the crack tip and this is simply because a crack is a notch with zero tip radius .
and The application of stress intensity factor k in respect to present fatigue crack tip is termed " linear elastic fracture mechanics "
Answer:
hello your question lacks the required question attached below is the missing diagram
Forces in GJ = -4.4444 i.e. 4.4444 tons
Forces in IG = 15.382 tons ( T )
Explanation:
Forces in GJ = -4.4444 i.e. 4.4444 tons
Forces in IG = 15.382 tons ( T )
attached below is the detailed solution
Answer:
T=kg·m^2/s^2
Explanation:
T = kg (m^2/s^2) m^3 /m^3
Here I wrote down the unit for every dimension.
T=kg m^2 / s^2
m^3 is divided between m^3, this is equal to 1.
Result: T=kg·m^2/s^2
PD: I'm not sure if this is what you ask for. I hope it helps
