Answer:
B
Explanation:
This occurs over the Pacific Ocean, so C and D are already wrong. El Nino heats the water and not cools it, so A is incorrect. So commonsense says that the answer is B.
 
        
             
        
        
        
Answer:
mechanical power used to overcome frictional effects in piping is 2.37 hp
Explanation:
given data 
efficient pump = 80% 
power input = 20 hp
rate = 1.5 ft³/s
free surface = 80 ft
solution
we use mechanical pumping power delivered to water is
 .............1
  .............1
put here value 
 = (0.80)(20)
  = (0.80)(20)
 = 16 hp
 = 16 hp 
and 
now we get change in the total mechanical energy of water is equal to the change in its potential energy
 ..............2
   ..............2
 
   
and that can be express as
 ..................3
     ..................3
so 
![\Delta {E_{mech}} = (62.4lbm/ft^3)(1.5ft^3/s)(32.2ft/s^2)(80ft)[\frac{1lbf}{32.2lbm\cdot ft/s^2}][\frac{1hp}{550lbf \cdot ft/s}]](https://tex.z-dn.net/?f=%5CDelta%20%7BE_%7Bmech%7D%7D%20%3D%20%2862.4lbm%2Fft%5E3%29%281.5ft%5E3%2Fs%29%2832.2ft%2Fs%5E2%29%2880ft%29%5B%5Cfrac%7B1lbf%7D%7B32.2lbm%5Ccdot%20ft%2Fs%5E2%7D%5D%5B%5Cfrac%7B1hp%7D%7B550lbf%20%5Ccdot%20ft%2Fs%7D%5D) ......4
      ......4
solve it we get 
 hp
 hp
so here 
due to frictional effects, mechanical power lost in piping
we get here 
 
  
put here value 
 = 16 -13.614
 = 16 -13.614
 = 2.37  hp
 = 2.37  hp 
so mechanical power used to overcome frictional effects in piping is 2.37 hp
 
        
             
        
        
        
Answer:

Explanation:
Using the expression shown below as:

Where, 
 is the number of vacancies
 is the number of vacancies
N is the number of defective sites
k is Boltzmann's constant = 
 is the activation energy
 is the activation energy 
T is the temperature
Given that:

N = 10 moles
1 mole = 
So, 
N = 
Temperature = 425°C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15  
So,  
T = (425 + 273.15) K = 698.15 K  
T = 698.15 K 
Applying the values as:

![ln[\frac {2.3}{6.023}\times 10^{-11}]=-\frac {Q_v}{1.38\times 10^{-23}\times 698.15}](https://tex.z-dn.net/?f=ln%5B%5Cfrac%20%7B2.3%7D%7B6.023%7D%5Ctimes%2010%5E%7B-11%7D%5D%3D-%5Cfrac%20%7BQ_v%7D%7B1.38%5Ctimes%2010%5E%7B-23%7D%5Ctimes%20698.15%7D)

 
        
             
        
        
        
Answer:
of 5 lb/ft and a concentrated service live load at midspan. .... length = 12 feet) to support a uniformly distributed load. Taking ... w 7..'{ 'f.- ~ s-·. 344 ft-kip. Fy : s-o ks I. 299 ft-kip. Li.. ::::- I 2.. }-t-. 150 ft-kip ..... The concrete and reinforcing steel properties are ... Neglecting beam self-weight . and based only on the ...... JI : Lf, 2. l.. ;VI.
Explanation: