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scoundrel [369]
3 years ago
10

Consider the reaction: HCN (aq) + H2O (l) ⇄ CN- (aq) + H3O + (aq) Which of the following statements will decrease the amount of

work the system could perform? (a) Boil off water from the container (increasing the concentration of all species) (b) Add solid NaOH to the reaction (assume no volume change) (c) Selectively remove CNfrom the solution (d) Add water to the reaction vessel (e) Increase the concentration of the HCN
Chemistry
1 answer:
alekssr [168]3 years ago
4 0

Answer: Option (b) is the correct answer.

Explanation:

The given chemical reaction shows that hydrogen cyanide acid has been added to water which results in the formation of hydronium ion and cyanide ion.

Also, when we add a base like sodium hydroxide (NaOH) to HCN then it will help in accepting a proton (H^{+}) from hydrogen cyanide. As a result, formation of CN^{-} anion will be rapid and easy.

This will make the system not to do any extra work. So, amount of work done by system will decrease.

Thus, we can conclude that out of the given options, add solid NaOH to the reaction (assume no volume change) will decrease the amount of work the system could perform.

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3 years ago
PLEASE I NEED HELP ASAP!!!!
miv72 [106K]

The percent yield of the calcium hydroxide is 84.5%.

<h3>What is stoichiometry?</h3>

Stoichiometry enables us to obtain the mass of a substance form the equation of the reaction.

The equation of the reaction is;

CaCO3 + 2HCl -----> CaCl2 + CO2 + H2O

Number of moles of X = 40.0 grams/100 g/mol = 0.4 moles

Number of moles of HCl = 850/1000 * 1 M = 0.85 moles

If 1 mole of CaCO3 reacts with 2 moles of HCl

0.4 moles of  CaCO3 reacts with  0.4 moles  * 2 moles/1 mole

= 0.8 moles of HCl

Hence X is the limiting reactant.

The reaction is 1:1 then the amount of CO2  produced is 0.4 moles

Mass of CO2 = 0.4 CO2 * 44 g/mol = 17.6 g

2) The reaction equation is; 2NaOH + CaCO3 --->  Ca(OH)2 + Na2CO3

Number of moles of X = 25.0 grams/100 g/mol =  0.25 moles

Number of moles of NaOH= 40/1000 L * 2 M = 0.08 moles

If 1 mole of X reacts with 2 moles of NaOH

0.25 moles  reacts with   0.25 moles   * 2 moles /1 mole

= 0.5 moles

NaOH is the limiting reactant

2 moles of NaOH produces 1 mole of CO2

0.08 moles of NaOH produces 0.08 moles * 1 mole/2 moles

= 0.04 moles of CO2

Theoretical yield of CO2 =  0.04 moles of CO2 * 74 g/mol = 2.96  g

Percent yield = 2.5 g/ 2.96  g * 100

= 84.5%

Learn ore about percent yield:brainly.com/question/17042787

#SPJ1

5 0
2 years ago
True or False. The amount of heat required to raise the temperature of an object by 1 degree celsius is heat capacity.​
Olenka [21]

this is exactly true..i know this answer

8 0
2 years ago
What is the number of moles of NaOH in 16.5 mL of 0.750 Molar NaOH?
Alchen [17]

Answer:

0.0165 (L) * 0.750 (mol/L) = 0.0124 mol NaOH in 16.5 mL

Explanation:

5 0
3 years ago
A beam of light has a wavelength of 24.0 μm ( μm = 10 -6m). What is its frequency?
vfiekz [6]

Answer:

Frequency = 1.25 ×10¹³ Hz

Explanation:

Given data:

Wavelength of light = 24.0  μm (2.4 ×10⁻⁵ m)

Frequency = ?

Solution:

Formula:

Speed of light = wavelength × frequency

Speed of light /wavelength = frequency

Frequency = 3×10⁸ m /s /2.4 ×10⁻⁵m

Frequency = 1.25 ×10¹³ s⁻¹

s⁻¹ = Hz

Frequency = 1.25 ×10¹³ Hz

6 0
3 years ago
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