Answer: “Salt and Water”.
Explanation: Strong Acids and Strong Bases each disassociate completely.
Sodium Hydroxide(aq) and Nitric Acid(aq):
NaOH -> Na+ + OH-
& HNO3-> H+ + NO3- when combined
Yield Na+ + NO3- + H2O; evaporate off the water, and Sodium Nitrate remains.
The final molarity of this diluted solution is equal to 6.0 M.
<u>Given the following data:</u>
- Initial molarity = 12.2 M
To calculate the final molarity of this diluted solution:
<h3>The formula for the molarity of a solution.</h3>
Mathematically, the relationship between the molarity of a solution and volume is given by the formula:
![MV = k\\\\M_1V_1 = M_2V_2](https://tex.z-dn.net/?f=MV%20%3D%20k%5C%5C%5C%5CM_1V_1%20%3D%20M_2V_2)
<u>Where:</u>
- M is the molarity of a solution.
- V is the volume of a solution.
Making
the subject of formula, we have:
![M_2 = \frac{M_1V_1}{V_2}](https://tex.z-dn.net/?f=M_2%20%3D%20%5Cfrac%7BM_1V_1%7D%7BV_2%7D)
Substituting the given parameters into the formula, we have;
![M_2 = \frac{12 \times 4.0}{8.0} \\\\M_2 = \frac{48}{8.0}](https://tex.z-dn.net/?f=M_2%20%3D%20%5Cfrac%7B12%20%5Ctimes%204.0%7D%7B8.0%7D%20%5C%5C%5C%5CM_2%20%3D%20%5Cfrac%7B48%7D%7B8.0%7D)
Final molarity = 6.0 M
Read more on molarity here: brainly.com/question/17138838
If my math is right, it should be around 4.33x10^23
To get this you need to find the atomic weight of MgI2, which is around 278. You divide the mass in grams by the atomic mass to find Moles, then you multiply the moles by Avogadros number: 6.022x10^23. Hope I was helpful