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-Dominant- [34]
3 years ago
14

2. Sa epikong binasa, sinusuong at nilalabanan ni Indarapatra ang mga halimaw ,

Chemistry
1 answer:
lutik1710 [3]3 years ago
5 0

Answer:

hindi sila magkapareho

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New nuclei and neutrons result from:
svet-max [94.6K]
I think the correct answer from the choices listed above is option C. New nuclei and neutrons result from <span>the splitting of an atom's nucleus. It is called nuclear fission where atoms are being split into smaller parts. Hope this answers the question. Have a nice day.</span>
3 0
3 years ago
Calculate the number of carbon atoms contained in 5.6 g of C2H4
miss Akunina [59]

Molecular mass of C₂H₄ is,

M = 2×12 + 4×1 g/mol

M = 28 g/mol

Moles of C₂H₄ in 5.6 g of C₂H₄ :

n = 5.6/28 mol

n = 0.2 mol

Now, 1 mol of C₂H₄ contains 2 moles of carbon.

So, number of moles of carbon are :

n = 0.4 mol

We know, 1 mol of any atom contains 6.022 × 10²³ atoms.

So, number of carbon atoms are :

N = 0.4 \times 6.022\times 10^{23} \\\\N = 2.409 \times 10^{23}

Hence, this is the required solution.

4 0
3 years ago
How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 43.6 grams of sodium hydroxide in
GaryK [48]

Answer is: 25.84  milliliters of sodium metal.

Balanced chemical reaction: 2Na + 2H₂O → 2NaOH + H₂.

d(Na) = 0.97 g/mL; density of sodim.

m(NaOH) = 43.6 g; mass of sodium hydroxide.

n(NaOH) = m(NaOH) ÷ M(NaOH).

n(NaOH) = 43.6 g ÷ 40 g/mol.

n(NaOH) =1.09 mol; amount of sodium hydroxide.

From chemical reaction: n(NaOH) : n(Na) = 2 : 2 (1: 1).

n(Na) = 1.09 mol.

m(Na) = 1.09 mol · 23 g/mol.

m(Na) = 25.07 g; mass of sodium.

V(Na) = m(Na) ÷ d(Na).

V(Na) = 25.07 g ÷ 0.97 g/mL.

V(Na) = 25.84 mL.

7 0
3 years ago
Convert 7.2 x 10^-5 from scientific notation into standard notation
Ghella [55]

Answer:

720 000

Explanation:

7.2

×

10

5

is already expressed in

standard form

I believe you mean express as

original number

To do this consider

10

5

or more generally

10

n

where n is an integer.

• If n > 0

move decimal point n places to the right

• If n < 0

move decimal point n places to the left

here n = 5 > 0, hence move decimal point 5 places to the right.

⇒

7

∙

2

→

720000

∙

⇒

7.2

×

10

5

=

720

000

Explanation:

6 0
3 years ago
How is a suspension different from a colloid?
Mashcka [7]

Answer:

Explanation:

Colloidal:

  • Colloid consist of the particles having size between 1 - 1000 nm i.e, 0.001- 1μm.  
  • The particles in colloid can not be seen through naked eye.
  • It is homogeneous.
  • We can not separate the colloidal through the filtration. The pore size of filter paper is 2μm. However it can be separated through the ultra filtration. In ultra filtration the pore size is reduced by soaking the filter paper in gelatin and then in formaldehyde. This is only in case of when solid colloidal is present, if colloid is liquid , there is no solid particles present and ultra filtration can not be used in this case.

Suspension:

  • The particle size in suspension is greater than 1000 nm.
  • These particles can seen through naked eye.
  • It is heterogeneous.  
  • The particles in suspension can be separated through the filtration.
3 0
3 years ago
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