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-Dominant- [34]
3 years ago
14

2. Sa epikong binasa, sinusuong at nilalabanan ni Indarapatra ang mga halimaw ,

Chemistry
1 answer:
lutik1710 [3]3 years ago
5 0

Answer:

hindi sila magkapareho

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What are the correct half reactions for the following reaction:
d1i1m1o1n [39]

Answer:

D. Zn → Zn²⁺ + 2e⁻, 2H⁺ + 2e⁻ → H₂.

Explanation:

  • It is a redox reaction that is consisted of two half-reactions:

Oxidation reaction:

Zn losses 2 electrons and is oxidized to Zn²⁺:

<em>Zn → Zn²⁺ + 2e⁻.</em>

<em></em>

Reduction reaction:

H⁺ gains 1 electron and is reduced to H:

<em>2H⁺ + 2e⁻ → H₂.</em>

<em></em>

<em>So, the right choice is: D. Zn → Zn²⁺ + 2e⁻, 2H⁺ + 2e⁻ → H₂.</em>

<em></em>

8 0
3 years ago
Read 2 more answers
Static charges can be applied to neutral objects by friction, induction or conduction. What do all of these methods utilize to c
MatroZZZ [7]
Electrons are valence and free moving so they take place in charge transfer
5 0
3 years ago
Be sure to answer all parts. For each of the following pairs of elements, state whether the binary compound they form is likely
andrew-mc [135]

Answer:

(a) Covalent bond. NF₃ (nitrogen trifluoride)

(b) Ionic bond. LiCl (lithium chloride)

Explanation:

<em>(a) N and F</em>

Nitrogen and fluorine are nonmetals, with high and similar electronegativities, so they form covalent bonds, in which they share pairs of electrons to complete the octet in their valence shell. N has 5 valence electrons so it will form 3 covalent bonds while each Cl has 7 valence electrons so it will form 1 covalent bond. As a result, the empirical formula is NF₃ (nitrogen trifluoride).

<em>(b) Li and Cl</em>

Lithium is a metal and Chlorine is a nonmetal. They have different electronegativities so they form an ionic bond, in which Cl gains 1 electron (7 valence e⁻) and Li loses 1 electron (1 valence e⁻). The empirical formula is LiCl (lithium chloride).

5 0
3 years ago
Which element has the ground state electron configuration 1s22s22p63s23p3?
Natalka [10]
Its phosphorus (P)In writing the electron configuration for Phosphorus the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for Phosphorous go in the 2s orbital. The next six electrons will go in the 2p orbital. The p orbital can hold up to six electrons. We'll put six in the 2p orbital and then put the next two electrons in the 3s. Since the 3s if now full we'll move to the 3p where we'll place the remaining three electrons. Therefore the Phosphorus electron configuration will be 1s22s22p63s23p3.
4 0
3 years ago
When solving an equation using Gay-Lussac's law, which of the following steps do not apply? A. List your knowns and unknowns. B.
suter [353]

Answer:

C. Plug the unknowns into the ideal gas law formula.

Explanation:

Gay-Lussac's law states that:

"For a constant mass of an ideal gas kept at constant volume, the pressure of the gas is directly proportional to its absolute temperature"

Mathematically, it can be written as:

\frac{p_1}{T_1}=\frac{p_2}{T_2}

where

p1 is the initial pressure

T1 is the initial temperature (in Kelvin)

p2 is the final pressure

T2 is the final temperature (in Kelvin)

Therefore, in order to solve for one of the 4 variables, the following steps must be adopted:

A. List your knowns and unknowns.

B. Convert temperature to kelvin.

D. Solve for the unknown.

While the following step is not needed:

C. Plug the unknowns into the ideal gas law formula.

Because we do not need to use the ideal gas law formula.

8 0
3 years ago
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