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-Dominant- [34]
3 years ago
14

2. Sa epikong binasa, sinusuong at nilalabanan ni Indarapatra ang mga halimaw ,

Chemistry
1 answer:
lutik1710 [3]3 years ago
5 0

Answer:

hindi sila magkapareho

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if the particles formed through fission have less mass than the starting material has the laaw of conversation of energy been br
Alexxandr [17]

The law of conservation of energy has not been broken, provided energy is released from the fission process.

<h3>What is the law of conservation of energy?</h3>

The law states that the total energy of a process is conserved. That is, the total energy or mass of a system before and after undergoing processing remains the same. However, some of the mass/energy can be converted to another form.

When a material undergoes fission, the sum total of the mass of the particles formed should be equal to the mass of the starting materials, provided that all other things remain the same.

However, if energy is released from the fission process, it means that some of the mass of the starting materials has been converted to energy and released to the environment.

More on the law of conservation of energy can be found here: brainly.com/question/20971995

#SPJ1

3 0
2 years ago
A student heats 10.52 g of sodium hydrogen carbonate in a crucible until the compound completely decomposes to sodium carbonate
saveliy_v [14]

Answer:

m_{Na_2CO_3}^{theoretical}=6.636gNa_2CO_3

Explanation:

Hello!

In this case, since the decomposition of sodium hydrogen carbonate is:

2NaHCO_3(s)\rightarrow Na_2CO_3(s)+H_2O(g)+CO_2(g)

Thus, since there is a 2:1 mole ratio between the sodium hydrogen carbonate and sodium carbonate, and the molar masses are 84.01 and 105.99 g/mol respectively, we obtain the following theoretical yield:

m_{Na_2CO_3}^{theoretical}=10.52gNaHCO_3*\frac{1molNaHCO_3}{84.01gNaHCO_3}*\frac{1molNa_2CO_3}{2molNaHCO_3}  *\frac{105.99gNa_2CO_3}{1molNa_2CO_3}\\\\ m_{Na_2CO_3}^{theoretical}=6.636gNa_2CO_3

Best regards!

4 0
3 years ago
If you start with 0.020 g of Mg, how many moles of H2 will you make if the reaction is complete?
irina [24]

If one starts with 0.020 g of Mg, 0.0008 moles of H2 would be made if the reaction is complete.

Going by the balanced equation of reaction in the image, 1 mole of Mg will produce 1 mole of H2 in a complete reaction.

If 0.020 g of Mg is started with:

mole of Mg = mass/molar mass

                        = 0.020/24.3

                            = 0.0008 moles

Since the mole of Mg to H2 is 1:1, thus, 0.0008 moles of H2 will also be made from the reaction.

More on stoichiometry can be found here: brainly.com/question/9743981

6 0
3 years ago
What is the molarity of formaldehyde in a solution containing 0.25 grams of formaldehyde per mL?
Vikentia [17]

Answer:

8.33mol/L

Explanation:

First, let us calculate the molar mass of of formaldehyde (CH2O). This is illustrated below:

Molar Mass of CH2O = 12 + (2x1) + 16 = 12 + 2 + 16 = 30g/mol

Mass of CH2O from the question = 0.25g

Number of mole CH2O =?

Number of mole = Mass /Molar Mass

Number of mole of CH2O = 0.25/30 = 8.33x10^-3mole

Now we can calculate the molarity of formaldehyde (CH2O) as follow:

Number of mole of CH2O = 8.33x10^-3mole

Volume = 1mL

Converting 1mL to L, we have:

1000mL = 1L

Therefore 1mL = 1/1000 = 1x10^-3L

Molarity =?

Molarity = mole /Volume

Molarity = 8.33x10^-3mole/1x10^-3L

Molarity = 8.33mol/L

Therefore, the molarity of formaldehyde (CH2O) is 8.33mol/L

3 0
3 years ago
Which of the following groups of elements are likely to be radioactive? (5 points) a Actinides b Noble gases c Transition metals
Nataly [62]

Answer:

Actinides

Explanation:

They are defined as "any of the series of fifteen metallic elements from actinium (atomic number 89) to lawrencium (atomic number 103) in the periodic table. They are all radioactive, the heavier members being extremely unstable and not of natural occurrence"

3 0
3 years ago
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