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Ulleksa [173]
3 years ago
15

Convert 325 cm to yards I need the answer ASAP

Physics
1 answer:
Ira Lisetskai [31]3 years ago
7 0
325 /91 = 3.571 yards
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I will give brainliest to whoever is correct)<br>help, with this science question! thanks ^w^
ira [324]

Answer: its C

Explanation:

8 0
3 years ago
Read 2 more answers
A series combination of two resistors, 7.25 ω and 4.03 ω, is connected to a 9.00 v battery.
almond37 [142]

a. 11.28\Omega

The equivalent resistance of a series combination of two resistors is equal to the sum of the individual resistances:

R_{eq}=R_1 + R_2

In this circuit, we have

R_1 = 7.25 \Omega\\R_2 = 4.03 \Omega

Therefore, the equivalent resistance is

R_{eq}=7.25 \Omega + 4.03 \Omega=11.28 \Omega

b. 5.8 V, 3.2 V

First of all, we need to determine the current flowing through each resistor, which is given by Ohm's law:

I=\frac{V}{R_{eq}}

where V = 9.00 V and R_{eq}=11.28 \Omega. Substituting,

I=\frac{9.00 V}{11.28 \Omega}=0.8 A

Now we can calculate the potential difference across each resistor by using Ohm's law again:

V_1 = I R_1 = (0.8 A)(7.25 \Omega)=5.8 V

V_2 = I R_2 = (0.8 A)(4.03 \Omega)=3.2 V

4 0
3 years ago
To answer this question, suppose that each vehicle is moving at 7.69 m/s and that they undergo a perfectly inelastic head-on col
Maurinko [17]

Answer:

Force(F) = -80,955.01 N

Explanation:

We need to first determine the impulse that the truck driver received from the car during the collision

So; m₁v₁ - m₂v₂ = (m₁m₂)v₀

where;

m₁ = mass of the truck = 4280 kg

v₁ = v₂ =  speed of the each vehicle = 7.69 m/s

m₂ = mass of the car = 810 kg

Substituting our data; we have:

(4280×7.69) - (810×7.69) = (4280+810)v₀

32913.2 - 6228.9 = (5090)v₀

26684.1 =  (5090)v₀

v₀ = \frac{26684.1}{5090}

v₀ = 5.25 m/s

NOW, Impulse on the truck = m (v₀ - v)

= 4280 × (5.25 - 7.69)

= 4280 ×  (-2.44)

= -10,443.2 kg. m/s

Force that the seat belt exert on the truck driver can be calculated as:

Impulse = Force × Time

-10,443.2 kg. m/s = F (0.129)

F = \frac{-10,443.2}{0.129}

Force(F) = -80,955.01 N

Thus, the Force that the seat belt exert on the truck driver = -80,955.01 N

4 0
4 years ago
A playground merry-go-round of radius R = 1.40 m has a moment of inertia I = 265 kg · m2 and is rotating at 11.0 rev/min about a
Tom [10]

Answer:

The value of new value of angular speed of merry go round.\omega_{2} = 0.96 \frac{rad}{sec}

Explanation:

Given data

r = 1.4 m

Moment of inertia I_{1} = 265 kg - m^{2}

N_{1} = 11 RPM

\omega_{1} = \frac{2 \pi N}{60}

\omega_{1} = \frac{2 \pi (11)}{60}

\omega_{1} = 1.15 \frac{rad}{sec}

From conservation of momentum principal

I_{1} \omega_{1}  = I_{2} \omega_{2} ------- (1)

I_{2} = m r^{2} + 265

I_{2} = 27 (1.4)^{2} + 265

I_{2} = 317.92 \ kg m^{2}

Put all the values in equation  (1)

265 × 1.15 = 317.92 × \omega_{2}

\omega_{2} = 0.96 \frac{rad}{sec}

This is the value of new value of angular speed of merry go round.

6 0
3 years ago
How much energy is needed to melt 150 g of ice at 0°C to water? (1)(Lf =3.34˟ 10⁵ J/Kg)
NARA [144]

Answer:

5.01×10⁴ J.

Explanation:

Applying,

q = Cm....................... Equation 1

Where q = amount of heat needed to melt the ice, m = mass of the ice, C = specific latent heat of ice.

From the question,

Given: m = 150 g = (150/1000) kg = 0.15 kg, C = 3.34×10⁵ J/kg

Substitute these values into equation 1

q = (0.15×3.34×10⁵)

q = 0.501×10⁵ J

q = 5.01×10⁴ J.

5 0
3 years ago
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