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3 years ago

An alloy is made up of more than one type of what?

Chemistry

1 answer:

pychu [463]3 years ago

4 0

More than one type of metallic elements.

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Amino axit X có công thức H2NCxHy(COOH)2. Cho 0,1 mol X vào 0,2 lít dung dịch H2SO4 0,5M, thu được dung dịch Y. Cho Y phản ứng v

Taya2010 [7]

Answer:

nH2SO4 = 0,1 mol

Đặt nNaOH = a; nKOH = 3a (mol)

Quy đổi phản ứng thành: {X, H2SO4} + {NaOH, KOH} → Muối + H2O

Ta có: nH+ = nOH- → 2nX + 2nH2SO4 = nNaOH + nKOH

→ 2.0,1 + 2.0,1 = a + 3a → a = 0,1

→ nH2O = nH+ = nOH- = 0,4 mol

BTKL: mX + mH2SO4 + mNaOH + mKOH = m muối + mH2O

→ mX + 0,1.98 + 0,1.40 + 0,3.56 = 36,7 + 0,4.18 → mX = 13,3 gam

→ MX = 13,3/0,1 = 133

→ %mN = (14/133).100% ≈ 10,526%

7 0

2 years ago

The radioactive atom 61/27 co emits a beta particle. write an equation showing the decay

pickupchik [31]

Answer:

$\rm _{27}^{60}\text{Co} \longrightarrow \, _{-1}^{0}\text{e} + \, _{28}^{60}\text{Ni}$

Explanation:

The unbalanced nuclear equation is

$\rm _{27}^{60}\text{Co} \longrightarrow \, _{-1}^{0}\text{e} + \, ?$

Let's write the question mark as a nuclear symbol.

$\rm _{27}^{60}\text{Co} \longrightarrow \, _{-1}^{0}\text{e} + \, _{Z}^{A}\text{X}$

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.

Then

60 = 0 + A, so A = 60 - 0 = 60, and

27 = -1 + Z, so Z = 27 + 1 = 28

Your nuclear equation becomes

$\rm _{27}^{60}\text{Co} \longrightarrow \, _{-1}^{0}\text{e} + \, _{28}^{60}\text{X}$

Element 28 is nickel, so the balanced nuclear equation is

$\rm _{27}^{60}\text{Co} \longrightarrow \, _{-1}^{0}\text{e} + \, _{28}^{60}\text{Ni}$

7 0

3 years ago

What is the first principle energy level called

Firlakuza [10]

Answer is s orbital. Hopes this helps

6 0

3 years ago

Read 2 more answers

How many grams of O2(g) are needed to completely burn 46.0 g C3H8(g)?

Veronika [31]

Answer:

167,3 grams of O2 (g)

Explanation:

According to the following balanced equation:

C3H8 + 5 02 ---> 3 CO2 + 4 H20

We calculate the mass of the moles:

5 mol O2 = 16grams/mol x2x 5= 160 grams/mol

1 mol C3H8= 3 x12 grams/mol + 8 x 1 gram/mol= 44 grams/mol

If 44 grams C3H8 react with--------- 160 grams O2

46 gramsC3H8 react with --------X = (46x160)/44 =167, 3 grams O2

8 0

4 years ago

After mitosis, you have 2 cells that are the same as the parent cell. Why is it that your first cell was not the same as your pa

ladessa [460]

Answer:

During MITOSIS, the parent, diploid (2n), cell is divided to create two identical, diploid (2n), daughter cells. ... After cytokinesis, the ploidy of the daughter cells remains the same because each daughter cell contains 4 chromatids, as the parent cell did.

4 0

3 years ago