Answer:
The temperature will decrease to 50 K
Explanation:
Step 1: Data given
Temperature = 127 °C = 400 K
Pressure = 2.00 atm
The pressure decreases to 0.25 atm
Volume and number of moles do not change
Step 2: Calculate the new pressure
p1/T1=p2/T2
⇒with p1 = The initial pressure = 2.00 atm
⇒with T1 = The initial temperature = 127 °C = 400 K
⇒with p2 = the new pressure = 0.25 atm
⇒with T2 = the new temperature = TO BE DETERMINED
2.00 atm / 400 K = 0.25 atm / T2
0.005 = 0.25 / T2
T2 = 0.25/0.005
T2 = 50 K
The temperature will decrease to 50 K
Answer:
major enantiomer = 90.5 %
minor enantiomer = 9.5 %
Explanation:
Assuming that the major isomer is in excess;
From, ee/2 + 50
ee = enantiomeric excess = 81%
% major
=81/2 + 50 = 90.5 %
% minor
= 100% - 90.5 %
% minor
= 9.5 %