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damaskus [11]
3 years ago
5

Some giant ocean waves have a wavelength of 25 m and a frequency of

Physics
1 answer:
kolezko [41]3 years ago
3 0

Answer:

Explanation:

The frequency equation for waves is

f=\frac{v}{\lambda} where f is the frequency, v is the velocity, and lambda is the wavelength. Filling in:

.26=\frac{v}{25} so

v = .26(25) and

v = 6.5 meters/second

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Two charged metallic spheres of radii, R = 10 cms and R2 = 20 cms are touching each other. If the charge on each sphere is +100
Molodets [167]

Answer:

200\times 10^{-6}j

Explanation:

We have given the radius of first sphere is 10 cm and radius of second sphere is 20 cm

So the potential of first sphere will be greater than the potential of the second sphere, so charge will flow from first sphere to second sphere

Let q charge is flow from first sphere to second sphere and then potential become same

So V=\frac{K(100-q)}{r_1}=\frac{K\times 100}{r_2}

200-100=2q+q

q=\frac{100}{3}=33.33nC

So V=\frac{K(100-q)}{r_1}=\frac{9\times 10^{9}\times (100-33.33)\times 10^{-9}}{10\times 10^{-2}}=6003V

We know that potential energy U=qV=33.33\times 10^{-9}\times 6003=200\times 10^{-6}j

8 0
3 years ago
Read 2 more answers
Help please!!! Physics circular motion
svp [43]

Answer:

2. 3.1415 m/s

3. 0.63m

4. 0.006 m/s^2

Explanation:

2. v=(2*pi*r))/T, put in values and solve.

3. Circumference=2*pi*radius, radius is 0.1m, plug in and solve.

4. a=(v^2)/r, (don't worry about converting to meters, since units are the same in kilometers, they will cancel out) plug in values and solve.

That's it!

6 0
2 years ago
A gas‑forming reaction produces 1.90 m 3 1.90 m3 of gas against a constant pressure of 179.0 kPa. 179.0 kPa. Calculate the work
goldfiish [28.3K]

Answer:

The work done is 3.4 × 10⁵ J.

Explanation:

Given:

Pressure of the gas produced (P) = 179 kPa

Volume of the gas produced (ΔV) = 1.90 m³

We need to find the work done in joules. For that, we don't need any conversion as the units are already in SI units which will give the result in Joules only.

Now, let us verify our results by using conversion factors and without using them.

Using conversion factors:

1 m³ = 1000 L

So, 1.90 m³ = 1.90 m³ × 1000 \frac{L}{m^3} = 1900 L

Also, 1 atm = 101.325 kPa

So, 179 kPa = 179 kPa × \frac{1\ atm}{101.325\ kPa} = 1.767 atm

Now, work done in a constant pressure process is given as:

Work = Pressure × Volume change

Work = P × ΔV

Work = 1.767 atm × 1900 L

Work = 3.36 × 10³ atm-L

Now, again using the energy conversion for work.

1 atm-L = 101.325 J

So, 3.36 × 10³ atm-L = 3.36 × 10³ atm-L × \frac{101.325\ J}{1\ atm-L} = 3.4 × 10⁵ J

Therefore, the work done is 3.4 × 10⁵ J.

Now, let us verify the above result without any conversion.

Work = P × ΔV = 179 × 1000 × 1.90 = 3.4 × 10⁵ J.

Therefore, the work done is same by both ways.

Hence the work done is 3.4 × 10⁵ J.

8 0
3 years ago
Which of the following statements is correct about the force of gravity between two objects? (a)It depends on the shape of the o
morpeh [17]

Answer:

(D) It is stronger when the objects are closer.

Explanation:

Newton's universal law 9f gravitation

8 0
3 years ago
Which two statements are true about a system?
weqwewe [10]

Answer:The correct options are:

1. A system is a group of objects analyzed as one unit.

2. Energy that moves across system boundaries is conserved.

Explanation:

A system is defined as group of interrelated or interacting items existing as a single unit or a whole to achieve a specific objective.Energy lost by the system is equal to the energy gained by the surroundings.

Two statements are true about a system:

  • A system is a group of objects analyzed as one unit.
  • Energy that moves across system boundaries is conserved.
3 0
3 years ago
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