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soldier1979 [14.2K]
3 years ago
13

A lab requires 20.5g of KNO₃. How many moles of KNO₃ are being used in the lab. Your answer should include a correct numerical s

et up. What is the approximate percent by mass of the water in the hydrated salt? [Show all work.] *

Chemistry
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0

Answer:

the answer is 0.2

Explanation:

we have a formula that mole= reacting mass/ molar Mass and the molar Mass of KNO3 is 101 so since mole is reacting mass/ molar Mass and our reacting mass is 20.5 then divided it by 101 it is equal to 0.2

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Be sure to answer all parts. The thermal decomposition of phosphine (PH3) into phosphorus and molecular hydrogen is a first-orde
amm1812

The given question is incomplete. The complete question is :

The thermal decomposition of phosphine (PH3) into phosphorus and molecular hydrogen is a first-order reaction: 4PH_3(g)\rightarrow P_4(g)+6H_2(g) The half-life of the reaction is 35.0 s at 680°C. Calculate the first order rate constant.

Answer: a) The first order rate constant is 0.0198s^{-1}

b) The time after which 95% reactions gets completed is 151 seconds

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

a) for finding the rate constant

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.693}{35.0s}=0.0198s^{-1}

The first order rate constant is 0.0198s^{-1}

b) for completion of 95 % of reaction

t=\frac{2.303}{k}\log\frac{100}{100-95}

t=\frac{2.303}{0.0198}\log\frac{100}{5}

t=151 s

The time after which 95% reactions gets completed is 151 seconds

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Answer:

17

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