Join my Kahoo t Pin-04454287 join if u like anime

What is another name for this equipment and what does it do to reduce the impact of coal use?

slega [8]

Coal-fire power plants.

I hope this helps ya!

5 0

3 years ago

What happened to the colored water and to the paper ambot after poking the plastic covering the glass? ( experiment current affa

konstantin123 [22]

Answer:

ok ok ok ok ok ok ok ok ok ok ok ok ok ikjk

o

Explanation:

fgghhh

3 0

3 years ago

HBr can be added to alkenes in either the absence or presence of peroxides (producing either the Markovnikov or the anti-Markovn

Dmitrij [34]

Answer:

1) 2-bromobutane

2) 1-bromobutane

Explanation:

In the HBr reaction, we will have a markovniknov reaction due to the carbocation formation. The Br- then would be added in the most substituted carbon of the double bond.

In the HBr/peroxide reaction we have the opposite case: an anti-markovnikov reaction. Therefore the Br- would be added in the least substitued carbon of the double bond.

3 0

3 years ago

When an object is thrown, the thrower pushes the object. This causes the object to move in a

bija089 [108]

Answer:

Gains Kinetic Energy

Explanation:

Kinetic energy (KE) is the energy inserted on the object in motion. Having gained this energy enerted upon, the body maintains this kinetic energy unless its speed changes.

3 0

3 years ago

Calculate the final pH of a solution made by the addition of 10 mL of a 0.5 M NaOH solution to 500 mL of a 0.4 M HA originally a

Allushta [10]

This question is not complete, the complete question is;

Calculate the final pH of a solution made by the addition of 10 mL of a 0.5 M NaOH solution to 500 mL of a 0.4 M HA originally at pH = 5.0 ( pKa = 5.0)

Neglect the volume change.

Options:

a) 6.10

b) 5.09

c) 7.00

d) 5.02

Answer:

the final pH of a solution is 5.02

Option d) 5.02 is the Correct Answer

Explanation:

Given the data in the question,

Initially pKa = pH; so ratio is 1:1

thus, 0.4 M acid and base

Now, moles of NaOH = molarity × volume = 0.5 × 10 = 5 mmol = 5 × 10⁻³ mol.

Going into 500 mL ( 0.5 L ) of solution

new molarity will be;

⇒ moles / volume = 5 × 10⁻³ / 0.5 = 0.01 M

ACID reacting with BASE

original concentration of acid = 0.4 - 0.01 = 0.39 M

original concentration of base = 0.4 + 0.01 = 0.41 M

so

pH = 5 + log( base/acid)

= 5 + log ( 0.41/0.39)

= 5 + log ( 1.0512)

= 5 + 0.021

pH = 5.02

Therefore the final pH of a solution is 5.02

Option d) 5.02 is the Correct Answer

5 0

3 years ago