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3 years ago

when 32.4 g of water vapor condenses, how much heat is given off? The heat of vaporization for water is 40.67 kj/mol

1 answer:

3 0

When a water vapor condenses, heat is being released from the process. This heat is called latent heat of vaporization since the phase change happens without any change in the temperature. This value is constant per mole of a substance as a function of pressure and temperature. For this problem, we are given the heat of vaporization at a certain T and P. We use this value to calculate the total heat released from the process. We calculate as follows:

Total heat released: 32.4 g ( 1 mol / 18.02 g ) (40.67 kJ / mol) = 73.12 kJ

Therefore, 73.12 kJ of heat is released from the condensation of 32.4 g of water vapor.

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How much heat (in kJ) would need to be removed to cool 150.3 g of water from 25.60°C to -10.70°C?

olga_2 [115]

Answer:

Q = -22.9 kJ

Explanation:

Given that,

Mass of water, m = 150.3 g

Water gets cool from 25.60°C to -10.70°C.

The specific heat of water, c = 4.2 J/g°C

The formula for heat needed is given by :

$Q=mc\Delta T\\\\Q=150.3\times 4.2 \times (-10.7-25.6)\\\\Q=-22914.738\\\\or\\\\Q=22.9\ kJ$

So, 22.9 kJ of heat is needed to be removed to cool.

8 0

3 years ago

Last friday the atmospheric pressure in our 2nd year lab was measured as 731 mmhg. Calculate the temperature at which water woul

faust18 [17]

Answer:

p1/T1=p2/T2

760mmHg/212°F=731mmHg/T2

T2= 203.91°F

760mmHg/100°C=731mmHg/T2

T2= 96.18°C

Explanation:

You'd have to choose in which units you want to express the temperature.

7 0

3 years ago

The cyanide ion (CN-1) is highly toxic, but can be remediated in solution by redox reaction with the hypochlorite ion (the princ

Katena32 [7]

Answer:

2.275x10⁶g of CN⁻¹ were dissolved in the sample

Explanation:

Molarity is defined as the ratio between moles of solute and liters of solution.

If a CN⁻¹ solution has a concentration of 25mM, there are 0.025 moles of CN⁻¹ per liter of solution.

If the sample has a colume of 3.5x10⁶L, moles of CN⁻¹ are:

3.5x10⁶L × (0.025moles / L) = 8.75x10⁴ moles of CN⁻¹ in the sample of water.

In grams (As molar mass of CN⁻¹ is 26g/mol):

8.75x10⁴ moles CN⁻¹ × (26g / mol) = 2.275x10⁶g of CN⁻¹ were dissolved in the sample

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3 years ago

Na: 1s22sC2pP3s C= D= E=

KengaRu [80]

Answer

1s22s22p63s1

Explanation:

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3 years ago

Which of the following types of equations will include spectator ions

krek1111 [17]

Answer:- B) Full ionic equation

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Balanced molecular equation:-

$BaCl_2(aq)+2AgNO_3(aq)\rightarrow Ba(NO_3)_2(aq)+2AgCl(s)$