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mafiozo [28]
3 years ago
15

Ca(OH)2 + H3PO4 = Ca3(PO4)2 + H2O

Chemistry
1 answer:
larisa [96]3 years ago
4 0
Make a quick chart with each element represented, and count them up. HINT - leave the polyatomic anions together - in this case, PO4

Left      Right
1     Ca  3
2      O   1
5      H   2
1    PO4 2

Begin by balancing like finding common denominators of fractions - apply to both sides:
I started by adding a 2 in front of H3PO4 on the left, them 6 in front of H2O on the right. Last, a 3 in front of Ca (OH)2. Then, re-count using the chart format to make sure you're right.

3Ca(OH)2 + 2H3PO4 = Ca3(PO4)2 + 6H2O

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For this heterogeneous system 2 A ( aq ) + 3 B ( g ) + C ( l ) − ⇀ ↽ − 2 D ( s ) + 3 E ( g ) the concentrations and pressures at
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Answer:

2.55*10^{11

Explanation:

Equation for the heterogeneous system is given as:

2A_{(aq)}  + 3 B_{(g)} + C_{(l)}      ⇄      2D_{(s)}    +     3E_{(g)}

The concentrations and pressures at equilibrium  are:

[A] = 9.68*10^{-2}M

P_B = 9.54*10^3Pa

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[D]=10.11M

P_E=9.56*10^4torr

If we convert both pressure into bar; we have:

P_B = 9.54*10^3Pa

P_B = (9.54*10^3)*\frac{1}{10^5} bar

P_B=9.54*10^{-2}bar

P_E=9.56*10^4torr

1 torr = 0.001333 bar

9.54*10^4 *0.001333 = 127.5 bar

K=\frac{[P_E]^3}{[A]^2[P_B]^3}

K=\frac{(127.5)^3}{(9.68*10^{-2})^2(9.54*10^{-2})^3}

K=2.55*10^{11

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