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Tju [1.3M]
3 years ago
9

1. Elements combine to form millions of

Chemistry
1 answer:
Gnom [1K]3 years ago
6 0

question no 1 answer is compounds

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Determine the pH of an HNO2 solution of each of the following concentrations:
Zepler [3.9K]

Answer:

i think that the answer is B

Explanation:

I DON

5 0
3 years ago
What is the molar mass of (NH4)3 PO4? 113g, 121g, 149g, 339g
allochka39001 [22]
(NH4)3PO4 :

N = 14 * 3 =  42
H = 1 * 12 = 12
P = 31 * 1 = 31
O = 16 * 4 = 64
-------------------------
42+12+31+64 =  149 g / mol

Hope this helps!.


7 0
3 years ago
Which electron has a higher probability of being found at 4 Å of the nucleus, one in a 2s orbital or one in a 2p orbital?
Lena [83]

Answer:

one in a 2s orbital

Explanation:

Because of the peak near the nucleus in the 2s curve there is a higher probability of finding a 2s within 4 Å of the nucleus. In a multi-electron atom an electron in a 2s orbital will have a lower energy than one in a 2p orbital

4 0
3 years ago
Would the molecules in a gas have more or less movement than the molecules in a solid ? PLEASE HELP WILL MARK BRAINLY
Sergeeva-Olga [200]

Molecules in a gas will have more movement than molecules in a solid. This is because the molecules in solid matter are packed very tightly together to maintain its shape, whereas with gases they are spaced much further apart and fairly free to move. Hope this helps!

6 0
3 years ago
Calculate the theoretical yield for the bromination of both stilbenes
podryga [215]

Answer:

cinnamic acid - 150 mg

cis-stilbene - 100 μL

trans- stilbene - 100 mg

pyridinium tribromide - 200-385 mg

For this data:

moles of cinnamic acid = 0.150 g/148.16 g/mol = 0.001 mols

Theoretical mass of dibromoproduct formed = 0.001 mol x 307.97 g/mol = 0.312 g

cis-stilbene (100 ul = 0.1 ml)

moles of cis-stilbene = 0.1 ml x 1.01 g/mol/180.25 g/mol = 0.00056 mols

Theoretical mass of dibromoproduct formed = 0.00056 mol x 340.05 g/mol = 0.19 g

trans-stilbene

moles of tran-stilbene = 0.1 g/180.25 g/mol = 0.00055 mols

Theoretical mass of dibromoproduct formed = 0.00055 mol x 340.05 g/mol = 0.19 g

Explanation:

4 0
2 years ago
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