<u>Answer:</u> The percent yield of the reaction is 68.68%.
<u>Explanation:</u>
To calculate the mass of salicylamide, we use the equation:
![\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}](https://tex.z-dn.net/?f=%5Ctext%7BDensity%20of%20substance%7D%3D%5Cfrac%7B%5Ctext%7BMass%20of%20substance%7D%7D%7B%5Ctext%7BVolume%20of%20substance%7D%7D)
Density of salicylamide = 1.06 g/mL
Volume of salicylamide = 3.65 mL
Putting values in above equation, we get:
![1.06g/mL=\frac{\text{Mass of salicylamide}}{3.65mL}\\\\\text{Mass of salicylamide}=(1.06g/mL\times 3.65mL)=3.869g](https://tex.z-dn.net/?f=1.06g%2FmL%3D%5Cfrac%7B%5Ctext%7BMass%20of%20salicylamide%7D%7D%7B3.65mL%7D%5C%5C%5C%5C%5Ctext%7BMass%20of%20salicylamide%7D%3D%281.06g%2FmL%5Ctimes%203.65mL%29%3D3.869g)
To calculate the number of moles, we use the equation:
.....(1)
Given mass of salicylamide = 3.869 g
Molar mass of salicylamide = 137.14 g/mol
Putting values in equation 1, we get:
![\text{Moles of salicylamide}=\frac{3.869g}{137.14g/mol}=0.0295mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20salicylamide%7D%3D%5Cfrac%7B3.869g%7D%7B137.14g%2Fmol%7D%3D0.0295mol)
The chemical equation for the conversion of salicylamide to iodo-salicylamide follows:
![\text{salicylamide }+NaI+NaOCl+EtOH\rightarrow \text{iodo-salicylamide }](https://tex.z-dn.net/?f=%5Ctext%7Bsalicylamide%20%7D%2BNaI%2BNaOCl%2BEtOH%5Crightarrow%20%5Ctext%7Biodo-salicylamide%20%7D)
By Stoichiometry of the reaction:
1 mole of salicylamide produces 1 mole of iodo-salicylamide
So, 0.0295 moles of salicylamide will produce =
of iodo-salicylamide
Now, calculating the mass of iodo-salicylamide from equation 1, we get:
Molar mass of iodo-salicylamide = 263 g/mol
Moles of iodo-salicylamide = 0.0295 moles
Putting values in equation 1, we get:
![0.0295mol=\frac{\text{Mass of iodo-salicylamide}}{263g/mol}\\\\\text{Mass of iodo-salicylamide}=(0.0295mol\times 263g/mol)=7.76g](https://tex.z-dn.net/?f=0.0295mol%3D%5Cfrac%7B%5Ctext%7BMass%20of%20iodo-salicylamide%7D%7D%7B263g%2Fmol%7D%5C%5C%5C%5C%5Ctext%7BMass%20of%20iodo-salicylamide%7D%3D%280.0295mol%5Ctimes%20263g%2Fmol%29%3D7.76g)
To calculate the percentage yield of iodo-salicylamide, we use the equation:
![\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100](https://tex.z-dn.net/?f=%5C%25%5Ctext%7B%20yield%7D%3D%5Cfrac%7B%5Ctext%7BExperimental%20yield%7D%7D%7B%5Ctext%7BTheoretical%20yield%7D%7D%5Ctimes%20100)
Experimental yield of iodo-salicylamide = 5.33 g
Theoretical yield of iodo-salicylamide = 7.76 g
Putting values in above equation, we get:
![\%\text{ yield of iodo-salicylamide}=\frac{5.33g}{7.76g}\times 100\\\\\% \text{yield of iodo-salicylamide}=68.68\%](https://tex.z-dn.net/?f=%5C%25%5Ctext%7B%20yield%20of%20iodo-salicylamide%7D%3D%5Cfrac%7B5.33g%7D%7B7.76g%7D%5Ctimes%20100%5C%5C%5C%5C%5C%25%20%5Ctext%7Byield%20of%20iodo-salicylamide%7D%3D68.68%5C%25)
Hence, the percent yield of the reaction is 68.68%.