The empirical formula or simplest formula
gives the smallest whole-number ratio of
the atoms present in a compound.It gives the
relative number of atoms of each
element present in the compound.The ratio will be 3.72 : 21.28
<span><span>KrF2‡ </span>5 <span>trigonal bipyramid</span></span>
Answer:
Manganese (II) Phosphate
Explanation:
Mn3(PO4)2 is the compound given in this question. Manganese is the metal and hence it will come first in the name. Along with the name of metal it is essential to determine the valency of the metals based on the compound structure.
Here 2 PO4 attaches with 3 Mn
Valence of PO4 is -3
So the total electrons contributed by PO4 is 3*2 = 6
Now Mn has 3 atoms in the compound. Thus, per atom the valency must be 2 in order to satisfy -6 charge of PO4
Thus, valency of Mn is 2
So, the name will be
Manganese (II) Phosphate.
Explanation: The given compound is an organic compound because it has hydrogen and carbon atoms in it.
Skeletal structure of an organic compound is defined as a structure which is composed of the skeletal atoms that are used to define a structure.
In organic chemistry, the skeletal atoms are hydrogen and carbon. The atoms other than hydrogen and carbon are termed as heteroatoms and are shown in the structure.
The skeletal structure of 3-methyl-1-butanethiol is given in the image attached.
Here, the functional group is thiol group which has a heteroatom S.