Answer:
0.045 moles
Explanation:
Given data:
Moles of CO = ?
Volume of gas = 1 L
Temperature and pressure = standard
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
n = PV/RT
n = 1 atm× 1L / 0.0821 atm.L/mol.K × 273 K
n = 1 atm.L / 22.41 atm.L/mol
n = 0.045 mol
Answer:
if i remember correctly i beleive its A 1.8 x 10^24
but im not for sure also i think you forgot the 24
Explanation:
Answer:
Explanation:
Hello!
In this case, since the heat involved during a heating process is computed in terms of mass, specific heat and temperature change as shown below:
Thus, since the heated mass of water was 88 g, the specific heat of water is 4.184 J/g°C and the temperature change is 6.0 °C, we can compute the heat as shown below:
Best regards!
180 km/s V= 25
explanation: i had the same assignment
