Answer:
m = 4.51 and n = -5
Explanation:
The average magnetic field strength of the Earth is 0.0000451 T. We need to write the value of magnetic field strength of the Earth in scientific notation. In scientific notation, any value is given by :
.........(1)
Where
m is a real number
n is any integer
Here,
.......(2)
On comparing equation (1) and (2), we get the values as :
m = 4.51 and n = -5
Hence, this is the required solution.
Answer:
Explanation:
A ) angular velocity ω = 2π / T
= 2 x 3.14 / 60
= .10467 rad / s
linear velocity v = ω R
= .10467 x 50
= 5.23 m / s
centripetal force = m v² / R
= mg v² / gR
= 834 x 5.23² / 9.8 x 50
= 46.55 N
B )
apparent weight
= mg - centripetal force
= 834 - 46.55
= 787.45 N
C ) apparent weight
= mg + centripetal force
= 834 + 46.55
= 880.55 N.
D )
For apparent weight to be zero
centripetal force = mg
mg = mv² / R
v² = gR
= 9.8 x 50
= 490
v = 22.13 m /s
time period of revolution
= 2π R /v
2 x 3.14 x 50 / 22.13
= 14.19 s
Yes fishnet cudhejeiei. Jen did she
Answer:
The focal length fe of the eyepiece is <em>2.86 cm</em>
Explanation:
Since we are given the telescope's magnification and the length of the tube, we can use the expressions
<em>M = f_o/fe (1)</em> and
<em>l = f_o + fe (2)</em>
where
- M is the telescope's magnification
- l is the length of the tube
- fe is the focal length of the eye-piece
Rearranging equation (2) to make f_o the subject of the formula, we get
<em>f_o = l - fe</em>
Substituting the above equation into equation (1) we get
<em>M = (l - fe)/fe ⇒ fe = l/(M +1)</em>
<em> ⇒ fe = 60/(20 + 1)</em>
⇒ <em>fe = 2.86 cm</em>
In longitudinal waves, the particles of the medium or a system displaces back and forth(parallel) in the direction of the propagation of waves. In transverse waves, the particles of the medium or a system displaces perpendicular to the direction of the propagation of waves. Therefore, C is correct.
