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ankoles [38]
3 years ago
7

How is electrostatic force impacted by charge and distance?

Physics
1 answer:
lesantik [10]3 years ago
7 0

Answer: In electrostatics, the electrical force between two charged objects is inversely related to the distance of separation between the two objects. Increasing the separation distance between objects decreases the force of attraction or repulsion between the objects. ... Electrostatic force and distance are inversely related.

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Sunny_sXe [5.5K]

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3 years ago
Write an expression for a transverse harmonic wave that has a wavelength of 2.5 m and propagates to the right with a speed of 13
lyudmila [28]

Answer:

y = 0.14 Cos\left ( 2.512x-34.66t \right )

Explanation:

wavelength, λ = 2.5 m

speed, v = 13.8 m/s

Amplitude, A = 0.14 m

The general equation of the transverse harmonic wave which is travelling right is given by

y = A Sin\left ( \frac{2\pi }{\lambda } (x - vt)+\phi \right  )

where, Ф is phase

At t = 0, x = 0 , y = 0.14 m

0.14 = 0.14 Sin Ф

Ф = π/2

So, the equation is

y = 0.14Sin\left ( \frac{2\pi }{2.5 } (x - 13.8t)+\frac{\pi }{2} \right  )

y = 0.14 Cos\left ( 2.512x-34.66t \right )

3 0
3 years ago
In the flow past a compression corner, the upstream Mach number and pressure are 3.5 and 1 atm, respectively. Downstream of the
yulyashka [42]

Answer:

\theta=23.7^{\circ}

Explanation:

The ratio of pressure 2 to 1 us 5.48/1= 5.48 rounded off as 5.5.

Referring to table A.2 of modern compressible flow then M_{\beta_1}=2.2

Also

M_{\beta_1}=M_1 sin \beta and making sin\beta the subject of the formula then

sin\beta=\frac {2.2}{3.5}\\\beta=38.94^{\circ}

Making reference to \theta-\beta-M diagram then

\theta=23.7^{\circ}

4 0
3 years ago
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