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zvonat [6]
3 years ago
14

What information does an empirical formula give?

Chemistry
1 answer:
r-ruslan [8.4K]3 years ago
3 0

Answer:

C. The lowest whole-number ratio of atoms in a molecule.

Explanation:

Hello there!

In this case, according to the definition of the empirical and the molecular equations, it is possible for us to consider the following example of molecular formula, C4H10, whose empirical formula is C2H5.

In such a way, it is possible for us to say that the empirical formula gives C. The lowest whole-number ratio of atoms in a molecule, as it is the result of the simplification of the molecular formula when possible.

Regards!

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____ help scientists understand processes in the natural world by providing simpler representations of those processes.
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Answer:

Models help scientists understand processes in the natural world by providing simpler representations of those processes.

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3 years ago
What change would you expect on the rate of theSN2 reaction of 1-iodo-2-methylbutane withcyanide ion if the nucleophile concentr
Ivenika [448]

Answer:

The reaction rate of the both questions remain unchanged.

Explanation:

      For question 1:  The reaction 1-iodo -2- methylbutane with cyanide ion is an SN2 reaction because the Alkyl halide is a primary alkyl halide. The rate of reaction is dependent on concentration of the nucleophile and the alkyl halide at the same. For the rate of reaction to be affected (increased or decreased), the concentration of nucleophile and the alkyl halide have to be altered.

      For question 2: The reaction of 2-iodo -2- methylbutane with ethanol is an SN1 reaction because the Alkyl halide is a tertiary alkyl halide. There are two-step reaction mechanism in this reaction. The first step is the rate determining step which determines the extent of the reaction and hence the rate of reaction. For the rate of reaction to be affected (increased or decreased), the concentration of the Alkyl halide alone will be altered. The rate of reaction is independent of the concentration of the nucleophile.

6 0
3 years ago
The 1H-NMR of a compound with molecular formula C6H12O2 consists of four signals: 1.1 (triplet, integrating to 3 Hydrogens), 1.2
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Answer:

Isopropyl propionate  

Explanation:

1. Information from formula

The formula is C₆H₁₂O₂. A six-carbon alkane would have the formula C₆H₁₄. The deficiency of two H atoms indicates the presence of either a ring or a double bond.

2. Information from the spectrum

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(b) Septet-doublet

A 1H septet and a 6H doublet is the classic pattern for a -CH(CH₃)₂ (isopropyl) group

(c) The rest of the molecule

The ethyl and isopropyl groups together add up to C₇H₁₂.

The rest of the molecule must have the formula CO₂ and one unit of unsaturation. That must be a C=O group.

The compound is either

CH₃CH₂-COO-CH(CH₃)₂ or (CH₃)₂CH-COO-CH₂CH₃.

(d) Well, which is it?

The O atom of the ester function should have the greatest effect on the H atom on the adjacent carbon atom.

The CH of an isopropyl is normally at 1.7. The adjacent O atom should pull it down perhaps 3.2 units to 4.9.  

The CH₂ of an ethyl group is normally at 1.2. The adjacent O atom should pull it down to about 4.4.

We see a signal at 5.0 but none near 4.4. The compound is isopropyl propionate.

3. Summary

My peak assignments are shown in the diagram below.

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