All categories

3 years ago

In what situation you would prefer to use a successive approximation ADC over flash ADC?

Engineering

1 answer:

Levart [38]3 years ago

8 0

Answer and Explanation:

Both both successive approximation normally known SAR type and flash type ADC are used for the conversion of analog signal to digital signal successive approximation type ADC are preferred over flash type when we need fix conversion time and better accuracy and if we have don/t matter with speed of the conversion because flash type has better speed of conversion than SAR type

You might be interested in

Lumber jacks use cranes and giant tongs to hoist their goods into trucks for transport. Fortunately, smaller versions of these d

Tems11 [23]

Complete Question

Lumber jacks use cranes and giant tongs to hoist their goods into trucks for transport. Fortunately, smaller versions of these devises are available for weekend warriors who want to play with their chain saws. Let us model the illustrated tongs as a planar mechanism that carries a log of weight 210 N. Given the following dimensions: 35 mm 10 mm 40 mm 230 mm 85 mm 45 mm 10 mm 35 mm 345 mm determine the force in N and moment in Nm that our worker exerts on the tongs. Also determine the pinching force magnitude in N that the tongs exert on the log; i.e. determine the horizontal force that the tong's teeth exert on the log. Assume the point E is centered between the tong's teeth.

The diagram for this question is shown on the first uploaded image

Answer:

The force P is $P= 210 N$

and the moment M is $M = -48.3N \cdot m$

The horizontal force that the tong teeth exerts is $F_T =89.67N$

Explanation:

First let denote the dimension to corresponding to the diagram

$a=35mm , b= 10mm, c= 40mm, d= 230mm, e= 85mm,f= 45mm,\\g= 10mm,h=35mm,i=345mm.$

Next looking at the diagram let us consider the vertical direction

At equilibrium

$\sum F_{vertical} =0$

This mean that

$P+ W = 0$

Since they are acting in opposite direction the equation becomes

$P - W = 0$

=> $P= W$

=> $P= 210 N$

At Equilibrium Moment about F gives

$\sum M_f = 0$

=> $F_T * (e +f + g+ h+ i) - F_T * (e+ f+g+ h+i) - W *d -M =0$

=> $M = -W *d$

=> $M = -210 * 0.230$

=> $M = -48.3N \cdot m$

Here $F_T$ is the horizontal force that the tong teeth exerts

Now let consider the part BAF of the system as shown on the second uploaded image

Now the angle $\theta$ is mathematically given as

$tan \theta = \frac{g+h}{a}$

=> $\theta = arctan \frac{g+h}{a}$

$= arctan (\frac{10+35}{35} )$

$=52.125^o$

Now at equilibrium the moment about A is

$\sum M_A = 0$

=> $P * (c+d) +M + F_{BC} cos \theta *f+F_{BC}sin\theta *(a+b) =0$

$210 * (0.040 + 0.230)-48.3+F_{BC} cos (52.125^o)*0.045+ F_{BC}sin(52.125^o)$ $* (0.035 +0.010) =0$

=> $10.29 +F_{BC} (0.02763+0.03552) =0$

=> $F_{BC} =\frac{10.29}{0.06315}$

=> $F_{BC} = - 162.925 N$

Looking at the forces acting on the teeth as shown on the third uploaded image

At Equilibrium the moment about D is

$\sum M_D = 0$

=> $\frac{W}{2} *d - F_T *(i+h) -F_{BC} cos \theta *h -F_{BC} sin \theta * (b+c) =0$

=> $\frac{210}{2} * 0.230 -F_T (0.345 +0.035) - (-162.925)cos(52.125^o) *0.035\\-(-162.925)sin(52.125^o)(0.010 +0.040) =0$

=> $34.081 = F_T(0.345 +0.035)$

=> $F_T =89.67N$

7 0

4 years ago

A ____________ is a term that originally was referring to a way to reproduce a technical drawing documenting an architectural or

larisa86 [58]

Answer:

The answer is blueprint.

Explanation:

Have a nice day or night!

7 0

2 years ago

Air within a piston-cylinder assembly executes a Carnot heat pump cycle, . For the cycle, TH 5 600 K and TC 5 300 K. The energy

Zolol [24]

Answer:

a) w = 125 kJ/kg

b) P = 76.23 kPa

Explanation:

Given details:

T_H = 600 k

T_c = 300 k

Rjected energy Q 250 kg

Pressure is 325 kPa

a) coefficient of performance is given as

$COP = \frac{Q}{W} = \frac{T_H}{T_H - T_C}$

$\frac{Q}{W} = \frac{600}{600 - 300}$

$\frac{Q}{W} = = 2$

SOLVING FOR W

$W = \frac{250}{2} = 125 kJ/kg$

b) from figure

$Q12 - W12 = \Delta U$

$\Delta U = 0$ due to same temp at point 1 and 2

Q12 = W12

$W12 = mRT_C ln\frac{V_2}{V_1}$

and we know that

P1V1 =P2V2 so

$W12 = mRT_C ln\frac{P_1}{P_2}$

$125 = 0.287 \times 300 ln\frac{P_1}{P_2}$

$ln\frac{P_1}{P_2} = 1.45$

$\frac{P_1}{P_2} = e^{1.45}$

$P_2 = \frac{325}{e^{1.45}}$

$P_2 = 76.23 kPa$

5 0

4 years ago

The formula for calculating risk considering risk perception is ?

s2008m [1.1K]

Answer:

risk = probability x loss

Explanation:

3 0

3 years ago

Adam wants to become a certified professional engineer what are the steps that you have to follow

Delicious77 [7]

Graduate from an ABET-accredited engineering program.
Pass the Fundamentals of Engineering (FE) exam.
Work as an engineer for four years.
Pass the Professional Engineering (PE) exam (you cannot take the PE exam without first passing the FE exam).

6 0

3 years ago