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3 years ago

12

3. In the picture, a girl with a weight of 540 N is balancing on

1 answer:

svet-max [94.6K]3 years ago

6 0

Answer:

340 N

Explanation:

<u>Force formula</u>

The force formula is defined by Newton's second law of motion: Force exerted by an object equals mass times acceleration of that object: F = m ⨉ a. To use this formula, you need to use SI units: Newtons for force, kilograms for mass, and meters per second squared for acceleration.

<u>Equilibrium</u>

It is a state of rest or balance due to the equal action of opposing forces. equal balance between any powers, influences, etc.; equality of effect. mental or emotional balance; equanimity: The pressures of the situation caused her to lose her equilibrium.<u> </u>

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Use the balanced equation given below to solve the following problem; Calculate the volume in liters of CO produced by the react

Elan Coil [88]

Answer: 40.3 L

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} Sb_2O_3=\frac{175g}{291.5g/mol}=0.600moles$

$Sb_2O_3+3C\rightarrow 2Sb+3CO$

According to stoichiometry :

1 moles of $Sb_2O_3$ produces = 3 moles of $CO$

Thus 0.600 moles of $Sb_2O_3$ will produce= $\frac{3}{1}\times 0.600=1.80moles$ of $CO$

Volume of $CO=moles\times {\text {Molar volume}}=1.80moles\times 22.4L/mol=40.3L$

Thus 40.3 L of CO is produced.

6 0

3 years ago

Leave the answer blank if no precipitate will form. (Express your answer as a chemical formula.) Formula of precipitate ZnCl2(aq

Rasek [7]

Answer:

1. Zn(OH)₂ (s)

2. Ag₂CO₃ (s)

3. Ni₃(PO₄)₂(s)

4. No reaction

5. (NH₄)₂CO₃(s)

Explanation:

Let's state the equations and we analyse some solubility and precipitation information:

ZnCl₂(aq) + 2KOH(aq) → Zn(OH)₂ (s) + 2KCl (aq)

All the salts from the halogens with group 1, are soluble.

The OH⁻ reacts to Zn cation in order to produce a precipitate. This is ok, but if the base is in excess, the Zn(OH)₂ will be soluble

K₂CO₃(aq) + 2AgNO₃(aq) → Ag₂CO₃ (s) ↓ + 2KNO₃(aq)

All salts from nitrate are soluble

All salts from carbonates are insoluble

2(NH₄)₃PO₄(aq) + 3Ni(NO₃)₂(aq) → Ni₃(PO₄)₂(s) ↓ + 6NH₄NO₃(aq)

Salts from phosphates are insoluble

All salts from nitrate are soluble

NaCl(aq) + KNO3(aq) → NO REACTION

All salts from nitrate are soluble

All the salts from the halogens with group 1, are soluble

Na₂CO₃(aq) + 2NH₄Cl(aq) → 2NaCl(aq) + (NH₄)₂CO₃(s) ↓

All salts from carbonates are insoluble

All the salts from the halogens with group 1, are soluble

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