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irga5000 [103]
3 years ago
5

Is there gravitational force between two students sitting in a classroom?

Physics
1 answer:
drek231 [11]3 years ago
8 0

Answer:

Yes.

Explanation: the magnitude of the force is extremely small because the masses of the students are small relative to Earth's mass.

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Convert the following angles in degrees to radians:<br><br>(a) 300°<br>(b) 18°<br>(c) 105°​
almond37 [142]

Answer:

a) 5.23599

b) 0.314159

c) 1.8326

Explanation:

5 0
2 years ago
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A satellite at a particular point along an elliptical orbit has a gravitational potential energy of 5100 MJ with respect to Eart
serious [3.7K]

To solve this problem we will apply the theorem given in the conservation of energy, by which we have that it is conserved and that in terms of potential and kinetic energy, in their initial moment they must be equal to the final potential and kinetic energy. This is,

E_{initial} = E_{final}

PE_{initial}+KE_{initial} = PE_{final}+KE_{final}

Replacing the 5100MJ for satellite as initial potential energy, 4200MJ for initial kinetic energy and 5700MJ for final potential energy we have that

KE_{final} = (PE_{initial}+KE_{initial} )-PE_{final}

KE_{final} = (5100+4200)-5700

KE_{final} = 3600MJ

Therefore the final kinetic energy is 3600MJ

5 0
3 years ago
The graph shows the displacement of a mouse
hram777 [196]

The farthest position the mouse reaches inside the tunnel is 4 meters into the tunnel.

From the graph,

The positions reached after,

5 s = 4 m

10 s = 2 m

20 s = 2 m

35 s = 3 m

40 s = 0 m

So the farthest position here is 4 m into the tunnel.

The rate of change of positions is displacement. So displacement will be change in initial and final positions divided by change in time.

s = Δx / Δt

Therefore, the farthest position the mouse reaches inside the tunnel is 4 meters into the tunnel.

To knw more about displacement

brainly.com/question/28609499

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5 0
11 months ago
Objects 1 and 2 attract each other with a electrostatic force of 36.0 units. If the charge of Object 1 is doubled AND the distan
melamori03 [73]

Answer:

8 units

Explanation:

F=(k*q1*q2)/(r^2)

K is a constant, q1 is charge of 1, q2 is charge of 2, r is distance between the two.

6 0
2 years ago
A 795-loop square armature coil with a side of 10. 5 cm rotates at 70. 0 rev/s in a uniform magnetic field of strength 0. 45 t.
Agata [3.3K]

The rms voltage output of the generator is 1.94 × 10⁻ ⁵ V.

RMS is an acronym for root mean squared. An RMS value is more than just the "amount of AC power that causes the same heating impact as an analogous DC power" or something along those lines.

No. of loop = 795

Diameter of the coil = 10.5 cm

Radius of the coil = 5.25 cm

Magnetic Field, B = 0.45 T

Time, t = 70.0 rev/s

              V_{rms} =\frac{NwAB}{\sqrt{2} }

Where,

              N = No. of loop

              A = Area of the coil

              B = Magnetic Field

              V_{rms} = Voltage rms

Area of the coil = πr²

                        = 86.57 cm²

w = 2π/t

   =( 2 × 3.141)/70.0

   = 0.089

V_{rms} =\frac{795*0.089*86.57* 0.45}{\sqrt{2} }\\\\V_{rms} =\frac{2756.36}{\sqrt{2} }\\\\\\V_{rms} =\frac{2756.36}{1.414 }\\\\V_{rms} = 1.94 * 10^-^5 V

Therefore, the rms voltage output of the generator is 1.94 × 10⁻ ⁵ V.

Learn more about rms voltage here:

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8 0
9 months ago
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