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zhannawk [14.2K]
2 years ago
8

If a bow holds 500J of potential energy as the arrow is pulled back, how much kinetic energy will the arrow have after it has be

en released?
Physics
1 answer:
ale4655 [162]2 years ago
4 0

Answer:

500J

Explanation:

The arrow will have an energy of 500J after it has been released from its state of rest.

This is compliance with the law of conservation of energy which states that "in every system, energy is neither created nor destroyed but transformed from one form to another".

  • The energy at rest which is the potential energy is 500J
  • This energy will be converted to kinetic energy in total after the arrow has been released.
  • This way, no energy is lost and we can account for the energy transformations occurring.
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igor_vitrenko [27]

The longer you spend reading and thinking about this question,
the more defective it appears.

-- In each case, the amount of work done is determined by the strength
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-- We know that the forces are equal, but we don't know anything about
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-- If one skateboard moves a few feet and comes to a stop, then you
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I don't think we know enough about the experimental set-up and methods
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8 0
2 years ago
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A 1. 0 μf capacitor is being charged by a 9. 0 v battery through a 10 mω resistor.
Advocard [28]

The potential across the capacitor at t = 1.0 seconds, 5.0 seconds, 20.0 seconds respectively is mathematically given as

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  • t=1.967v
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<h3>What is the potential across the capacitor?</h3>

Question Parameters:

A 1. 0 μf capacitor is being charged by a 9. 0 v battery through a 10 mω resistor.

at

  • t = 1.0 seconds
  • 5.0 seconds
  • 20.0 seconds.

Generally, the equation for the Voltage is mathematically given as

v(t)=Vmax=(i-e^{-t/t})

Therefore

For t=1

V=5(i-e^{-1/10})

t=0.476v

For t=5s

V2=5(i-e^{-5/10})

t=1.967

For t=20s

V2=5(i-e^{-20/10})

V2=4.323v

Therefore, the values of voltages at the various times are

  • t=0.476v
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Read more about  Voltage

brainly.com/question/14883923

Complete Question

A 1.0 μF capacitor is being charged by a 5.0 V battery through a 10 MΩ resistor.

Determine the potential across the capacitor when t = 1.0 seconds, 5.0 seconds, 20.0 seconds.

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Consider a venturi with a small hole drilled in the side of the throat. This hole is connected via a tube to a closed reservoir.
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Answer:

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