If a bow holds 500J of potential energy as the arrow is pulled back, how much kinetic energy will the arrow have after it has be
1 answer:
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PART a)
As we know that gravitational potential energy is given by the formula
here we can see that gravitational potential energy inversely varies with the distance
so here when distance from the sun is minimum then magnitude of gravitational potential energy is maximum while since it is given with negative sign so its overall value is minimum at that position
So gravitational potential energy is minimum at the nearest point and maximum at the farthest point
PART b)
Since we know that sum of kinetic energy and potential energy is constant here
so the points of minimum potential energy is the point where kinetic energy is maximum which means speed is maximum
So here speed is maximum at the nearest point
Part C)
since gravitational potential energy inversely varies with distance so it's graph will be like hyperbolic graph with distance
Answer:
Explanation:
First, let's find the voltage through the resistor using ohm's law:
AC power as function of time can be calculated as:
(1)
Where:
Because of the problem doesn't give us additional information, let's assume:
Evaluating the equation (1) in t=3600 (Because 1h equal to 3600s):