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OlgaM077 [116]
3 years ago
13

Consider the following three-step reaction pathway.

Chemistry
1 answer:
Alenkinab [10]3 years ago
7 0

Answer:

NO \longrightarrow N_2O_2 \longrightarrow N_2O \longrightarrow N2

Explanation:

The intermediates are the products of all the steps of the reaction pathway, with the exception of the last one. So the intermediates will be:

  • N2O2 from the first step
  • N2O from the second step

The list from reactant to final product:

NO \longrightarrow N_2O_2 \longrightarrow N_2O \longrightarrow N2

<em>Note: the water is considered a by-product, given that is not the product of interest in this steps.</em>

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You must answer all questions to get credit for this assignment. Use the notes above and/or the textbook to help you find the an
Allisa [31]

Explanation:

(1).  It is known that in a reaction equation, reactants are placed or written on left hand side and products are written on the right hand side.

For example, N_{2} + 3H_{2} \rightarrow 2NH_{3}

Hence, in a reaction equation you start with the reactants and end up with the products.

(2).  The number of atoms in a reaction will remain the same because according to the law of conservation of mass, mass of reactants will be equal to the mass of products.

Therefore, number of atoms on the reactant side will be equal to the number of atoms on product side.

7 0
3 years ago
L = 5 m, w = 1 m, h = 3 m<br><br> 15 m3<br> 5 m2<br> 30 m2<br> 9 m3<br> 7.5 m3
melomori [17]

Volume of Cuboid :

  • l × w × h

  • 5 × 1 × 3

  • 15 m³
6 0
2 years ago
Which statement explains why large atoms are more reactive than small atoms?
Lunna [17]

A. Large atoms have valence electrons farther from the nucleus and lose them more readily, so they are more reactive than small atoms.

For example, the valence electron of a small atom like Li is tightly held. <em>Lithium gently fizzes</em> on the surface as it reacts with the water to produce hydrogen.

In contrast, the valence electron of a large atom like Cs is so loosely held that <em>cesium exlodes </em>on contact with water.

8 0
3 years ago
To understand the relation between the strength of an acid or a base and its pKa and pKb values. The degree to which a weak acid
elena-14-01-66 [18.8K]

Answer:

pKa = 3.675

Explanation:

  • pKa = - Log Ka

∴ <em>C</em> X-281 = 0.079 M

∴ pH = 2.40

let X-281 a weak acid ( HA ):

∴ HA ↔ H+ + A-

⇒ Ka = [H+] * [A-] / [HA]

mass balance:

⇒<em> C</em> HA = 0.079 M = [HA] + [A-]

⇒ [HA] = 0.079 - [A-]

charge balance:

⇒ [H+] = [A-] + [OH-]... [OH-] is negligible; it comes from to water

⇒ [H+] = [A-]

∴ pH = - log [H+] = 2.40

⇒ [H+] = 3.981 E-3 M

replacing in Ka:

⇒ Ka = [H+]² / ( 0.079 - [H+] )

⇒ Ka = ( 3.981 E-3 )² / ( 0.079 - 3.981 E-3 )

⇒ Ka = 2.113 E-4

⇒ pKa = - Log ( 2.113 E-4 )

⇒ pKa = 3.675

8 0
3 years ago
What can you say about the reactants of photosynthesis and the products of cellular respiration? pls don't search this up on gòo
KatRina [158]

Answer: The products and reactants for photosynthesis are reversed in cellular respiration: The reactants of photosynthesis are carbon dioxide and water, which are the products of cellular respiration. The reactants of cellular respiration are oxygen and sugar, which are the products of photosynthesis.

Explanation:

8 0
3 years ago
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