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OlgaM077 [116]
3 years ago
13

Consider the following three-step reaction pathway.

Chemistry
1 answer:
Alenkinab [10]3 years ago
7 0

Answer:

NO \longrightarrow N_2O_2 \longrightarrow N_2O \longrightarrow N2

Explanation:

The intermediates are the products of all the steps of the reaction pathway, with the exception of the last one. So the intermediates will be:

  • N2O2 from the first step
  • N2O from the second step

The list from reactant to final product:

NO \longrightarrow N_2O_2 \longrightarrow N_2O \longrightarrow N2

<em>Note: the water is considered a by-product, given that is not the product of interest in this steps.</em>

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laiz [17]

Answer:

The correct answer is 160.37 KJ/mol.

Explanation:

To find the activation energy in the given case, there is a need to use the Arrhenius equation, which is,  

k = Ae^-Ea/RT

k1 = Ae^-Ea/RT1 and k2 = Ae^-Ea/RT2

k2/k1 = e^-Ea/R (1/T2-1/T1)

ln(k2/k1) = Ea/R (1/T1-1/T2)

The values of rate constant k1 and k2 are 3.61 * 10^-15 s^-1 and 8.66 * 10^-7 s^-1.  

The temperatures T1 and T2 are 298 K and 425 K respectively.  

Now by filling the values we get:  

ln (8.66*10^-7/3.61*10^-15) = Ea/R (1/298-1/425)

19.29 = Ea/R * 0.001

Ea = 160.37 KJ/mol

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LUCKY_DIMON [66]

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Answer:

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Explanation:

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