Explanation:
... in every interaction, there is a pair of forces acting on the two interacting objects. The size of the force on the first object equals the size of the force on the second object. The direction of the force on the first object is opposite to the direction of the force on the second object. Forces always come in pairs - equal and opposite action-reaction force pairs.
Answer:
As a science fair project, you want to launch an 950g model rocket straight up and hit a horizontally moving target as it passes 33.0m above the launch point. The rocket engine provides a constant thrust of 20.0N . The target is approaching at a speed of 18.0m/s . At what horizontal distance between the target and the rocket should you launch?
= 43.56m
Explanation:
acceleration =
(20 - (0.95 * 9.8) )/ (0.95)
= 10.68 / 0.95
= 11.24 m/s²
we use
s = ut + (1/2) at²
Given that
s= 40
u =0
s = 0 * t + (1/2) (11.24)t²
t = √(66/1.24)
t = √5.87
t = 2.42sec
hence
Horizontal distance = 18 * 2.42
= 43.56m
Answer:
The alligator will take t = 10 s to reach the final speed of 35 m/s
Explanation:
As we know that the initial speed of the alligator is 5 m/s
then it accelerate by given acceleration to reach the final speed of 35 m/s
so we will have
now we have
Answer:
The electric field at the location of the point charge is defined as the force F divided by the charge q: Figure 23.1. Electric force between two electric charges. The definition of the electric field shows that the electric field is a vector field: the electric field at each point has a magnitude and a direction.
The answer to this question is:
C-"That moving clocks run slower"
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